Question

(a) A rope is wrapped tightly around a wheel with a radius of 3 feet. If the radius of the wheel is increased by 3 feet to a radius of 6 feet, by how much must the rope be lengthened to fit around the wheel? (Round your answer to two decimal places.)
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(b) Consider a rope wrapped around the Earth's equator. The radius of the Earth is about 4000 miles. That is 21,120,000 feet. Suppose now that the rope is to be suspended exactly 9 feet above the equator. By how much must the rope be lengthened to accomplish this? (Round your answer to one decimal place.)
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Answer 1

thanks

|_ @ Accoroling to questión. Let wheel radious (2) = 3 feet - increased radious s'= 6 feet Rope length - 27 godieus Lengthened Rope = Mew length - old. Loogte = 278'- zar .-) 27 (6-3) = 2*3*7 => 6 ł » 18.85 feet © According to question Radius of earth (R)= 21720 000 feet . Let 9 feet above the equator R=R+9 => 21120000 +9 = 21120009 * Lengthened rope = 27R - ZAR = 20 (R+9) – 21R = ñ(9) = 10K - 56.57 feet