Question

The result of the instructions: mov ax,e275                       and ax, 0a79dh 4aa2 4ba2 Aa42 none of them...

The result of the instructions: mov ax,e275                       and ax, 0a79dh

  1. 4aa2
  2. 4ba2
  3. Aa42
  4. none of them

The correct way to put the address of the first element in a register

  1. lea
  2. loop
  3. for
  4. none of them

To make only bit 2 of bx zero without changing any other bits we use

  1. and bx, 0fff0h
  2. and bx, 0fff4
  3. and bx, 0fff4h
  4. none of them

Suppose you want to calculate ebx mod 8

  1. and ebx, 0fffffff0h
  2. and ebx, 00000007h
  3. and ebx, 00000008h
  4. none of them

atod is a

  1. Macro
  2. Procedure
  3. Instruction
  4. none of them
0 0
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Answer #1

1. b. 4ba2

Adding both will give this result

2. a. lea

lea is used for laoding effective address

3. a. and bx 0fff0h

Only two bits will differ using this operation.

4. a. and ebx 0fffffff0h

This line is used to calculate ebx mod 8

5. a. macro

atod is a macro.

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