Question

26. 160. g Fe203 (s) and 84.0 g CO (g) are combined and allowed to react as follows: Fe203 (s)+3 CO (g) -2 Fe (s) +3 CO2 (g) When the reaction is complete, 93.5 g of Fe (s) has formed. What is the percent yield of the reaction? A. 265% B. 43.1% C. 67.2% D. 83.7% E. 100%

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Answer #1

No. of moles = weight / Molecular weight

a6. no.of moles op Fe2q: 160 , 9 1609用比 NO of moles of Co 84-0 28 1m* 11一千

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