Question

Can some expert help me step by step solution below questions please. The red circle are the right answers but show me your work how and why the answer are correct..

1. A water tank with a height of 10 feet and a diameter of 5 feet is accidentally punctured at the very bottom of its side wall. What is the maximum velocity that can be expected from the water flowing out of the hole if the tank is completely full? a. 10 ft/s b. 15 ft/s c. 20 ft/s d. 25 ft/s - 2S, 39 f If the puncture hole is 6 inches in diameter, what is the maximum volumetric flow rate that can be expected? Refer to Question 1. a,) 1 ft/s b. 3 ft3/s C5 ft3/s How long will it take the tank to drain to a half full level? a. 10 s b. 25 s с. 40s d. 55 s 4. Which of the following equations is most appropriate for use in Questions 1-2? a. Euler Equation b. Linear Momentum Equation c. Steady-Flow Energy Equation a) Torricelli Equation

Answer 1

Given that Tank height = H = 10 feet Tank dia = 5 feet orfice = dia = 6 in = 6 times 1/12 = 0.5 feet velocity of orfice = v = squareroot 2 g H g = 32.2 ft/sec^2 v = squareroot 2 times 32.2 times 10 = 25.37 ft/sec so, Answer is option d for first question flow rate = a = av a = Area of orfice = pi/4 times (0.5)^2 = 0.196 ft^2 Q = 0.196 times 25.37 = 4.98 ft^3/sec simeq 5 ft^3/sec Q = 5 ft^3/sec so, option Time taken to drain to a half full level = t t = 2A/a squareroot 2g (squareroot n_1 - squareroot n_2) A = Area of tank A = pi/4 times 5^2 = 1963 ft^2 a = area of orfice = 0.196 ft^2 t = 2 times 19.63/0.196 times squareroot 2 times 32.2 times (squareroot 10 - squareroot 5) = 23.11 sec t = 23.11 simeq 25 sec, so option b Toricelli Equation, velocity formula = v = squareroot 2