Pretest |
Posttest |
Difference |
D2 |
3 |
4 |
-1 |
1 |
2 |
7 |
-5 |
25 |
4 |
6 |
-2 |
4 |
2 |
4 |
-2 |
4 |
1 |
5 |
-4 |
16 |
5 |
8 |
-3 |
9 |
6 |
9 |
-3 |
9 |
3 |
8 |
-5 |
25 |
2 |
6 |
-4 |
16 |
3 |
7 |
-4 |
16 |
Sum = 31 |
Sum = 64 |
Sum = -33 |
Sum = 125 |
Mean = 3.1 |
Mean = 6.4 |
Mean = -3.3 |
Mean – 12.5 |
Answer:-
Given that:-
Paired Samples Statistics, Paired Samples Correlations, and Paired Samples Test..
Given Sample size n = 10\For the score difference we have
Null and Alternative Hypothesis:
: The two means are Same
: The two means are different
Test Statistic:
=
= -7.802
(using t table)
Since that we Reject
There is enough euiclence to claim that population mean is different than .
Calculate the t value using SPSS. Please show your SPSS output. You should have 3 tables:...
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