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1. All (identical) firms in a competitive industry have the following long-run total cost curve: C(q) = q3 – 10q2 + 369 where

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Answer #1

Cost function of a firm is given,

\large C = q^3 - 10q^2 + 36q

In the long run equilibrium the firms earn zero economic profit thus the price is equal to minimum ATC. We are required to minimize the ATC.

\large ATC =\frac{C}{q} = \frac{q^3 - 10q^2 + 36q}{q}

\large ATC = q^2 - 10q + 36

Differentiating ATC wrt q we get

\large ATC' = \frac{d(q^2 - 10q + 36)}{dq}

\large \implies ATC' = 2q - 10

The first order condition of minimization is that the first derivative must be equal to zero.

\large \implies ATC' = 2q - 10 = 0

\large \implies 2q = 10

\large \implies q = 5 \ units

Again differentiating ATC wrt q

\large ATC'' = \frac{d(2q - 10)}{dq}

\large ATC'' = 2

The SOC of minimization. Is that the second derivative must be a positive number. As we can see both condition is satisfied. Hence, ATC will be minimum at q = 5 units.

Minimum ATC = $ 11 per unit

\large ATC = q^2 - 10q + 36

\large \implies ATC = 5^2 - 10\times 5 + 36

\large \implies ATC = 25 - 50+ 36

\large \implies ATC = \$ \ 11

A. Long run equilibrium price = $ 11 per unit.

The long run supply curve is constant and parallel to the horizontal axis.

B. Given, Q = 111 - P

Q = 111 - 11 = 100

Market demand = 100 units.

Quantity supplied by each firm, q = 5 (calculated above)

\large Number \ of \ firms = \frac{100}{5} = 20

Number of firms in long run = 20.

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