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Test the claim that the proportion of people who own cats is smaller than 80% at the 0.05 significance level The null and alt
The test statistic is: (to 2 decimals) (to 4 decimals, if your p-value is less than 0.0001, you may The p-value.is enter 0))
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Answer #1

Hypothesis: H_0:p=0.80 VS  H_a:p<0.80

The test is one tailed test

Gievn : n=200 , X=148 , The estimate of the sample proportion is , \hat{p}=\frac{X}{n}=\frac{146}{200}=0.73

The test statistic is ,

Z_{stat}=\frac{\hat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}=\frac{0.73-0.80}{\sqrt{\frac{0.80(1-0.80)}{200}}}=-2.47

The p-value is ,

p-value=P(Z>|Z_{stat}|)=P(Z>2.47)=1-P(Z\leq 2.47)=1-\Phi(2.47)

=1-0.9932=0.0068 ; From standard normal distribution table

Decision : Here , p-value=0.0068<0.05

Therefore , reject the null hypothesis.

Conclusion : Hence , there is sufficient evidence to support the claim that the proportion of people who own cars is smaller than 80% .

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