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If the pendulum,as shown below, is released from the horizontal position with the length from the pendulums centre of mass to its axis of rotation being 2.52 m, the velocity of its bob in the vertical position isImage for If the pendulum,as shown below, is released from the horizontal position with the length from the pendulums ce

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Answer #2

mgh = (1/2)*m*v^2......

v = sqrt(2*g*h)= sqrt(2*9.8*2.52) = 7.027 m/sec

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Answer #3

From the law of conservation of energy, the kinetic energy at the highest point is equal to the potential energy at its mean position.

       0.5mv^2 = mgh

               v = sqrt (2gh)

                  = sqrt (2*9.8*2.52) = 7.03 m/s

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