mass of KClO3 = 66.8 g
molar mass of KClO3 = 122.55 g/mol
mol of KClO3 = (mass)/(molar mass)
= 66.8/122.55
= 0.5451 mol
According to balanced equation
mol of O2 formed = (3/2)* moles of KClO3
= (3/2)*0.5451
= 0.8176 mol
mass of O2 = number of mol * molar mass
= 0.8176*32
= 26.2 g
Answer: 26.2 g
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