so the value of Bx=0.
if helpful give ?.
thank you.
Solve for reaction forces
. Simply Supported beam with an extra roller support. Material: Aluminum Alloy 6061 T6 1.5 in. 1.0 in. 300 lb 50 lb/ft 2.5 ft. 5 ft. 5 ft.
please show your steps
200 lb 400 lb 4 ft - to2 ft2 ft → EI = 1.9 x 105 lb. ft2 FIGURE P16-22 16-20 to 16–25 See Figs. P16-20 to P16–25. Determine the deflection at the midspan C of each simply supported beam subjected to the loads shown. The flex- ural rigidity of each beam is indicated. QUESTION 24 Consider Problem-CC. What is the magnitude of the mid-span deflection caused by the 200 LB load? 0.0349 ft 0.0217 ft...
WD= 1 k/ft WL 2.0 k/ft 17in 20 in 4 # 9 - 20 ft 12 in. 21 in. The simply-supported beam shown above is comprised of class 5000 concrete and grade 60 rebar. Assume that the beam uses #3 stirrups (not shown) and has 1.5" of concrete cover (to the stirrups) on all sides (a) (20%) Determine the maximum instantaneous deflection for the unfactored (i.e. "service") dead load
WD= 1 k/ft WL 2.0 k/ft 17in 20 in 4 #...
a simply supported beam is loaded by a uniformly distributed
load of 200 lb/ft as shown in the figure. the cross section is made
of many wooden pieces as shown. given that the lag screws to be
used are ½ in in diameter and the allowable shear force in each lag
screw is 500 lb, determine the longitudinal spacing required for
lag screws at a and b. also, find the displacement and rotation at
5 ft.
10in NA. 4in Sin...
Problem 1. Given the 3-D sketch as shown of a tripod stand with a 300 ft"lb moment applied to the top at D (applied by a wrench). The tripod base is an equilateral triangle with 2 ft on each side. The height of the stand is 4 ft. Find the Resultant Force at points A, B, and C. The moment at D is in a parallel plane to the plane A, B and C are in. D 300 ft*lb h=4ft...
3. Analyze the system shown in Figure 3. (40 points) Copyright © McGraw-Hill Education. Permission required for reproduction or display 300 lb/ft - 4 ft 2 ft2 ft 300 lb Figure 2: Simply supported beam subject to a distributed load and a concentrated force Note: the Concentrated force at Point D induces a force on the beam and a moment on the beam both at Points C 3. Solve for the internal forces and moments in each region using integration...
The beam supports the triangular distributed load shown below
with wmax=625 lb/ft. The reactions at A and B are
vertical.
<HW #1 Problem 1.15 The beam supports the triangular distributed load shown below with wax 625 lb/ft. The reactions at A and B are vertical. 6ft 4545 6 ft 6ft Part A Determine the resultant internal loadings on the cross section at point C Express your answers, separated by commas, to three significant figures. vec kip, kip kip-ft Submit
Solve and label the HNMR and CNMR
Unknown #2 CgH180 3.5 3.0 2.5 2.0 1.5 1.0 f1 (ppm) 0 4 3 2 0 f1 (ppm)
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let w = 7.0 kips/ft, a= 9.0 ft, and b= 20.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions.Calculate the reaction forces By and Cy acting on the beam. Positive values for the reactions are indicated by...
P9.037 A cantilever beam supports the loads shown. The cross-sectional dimensions of the shape are also shown. Assume LAB-2.5 ft, LBc 7.5 ft, w 1500 lb/ft, P-2100 lb, b-15 in., d-8 in., t 0.45 in. Determine (a) the maximum horizontal shear stress. (b) the maximum compression bending stress. (c) the maximum tension bending stress BC MB Answers: ksi ƠC,ma,- (b) ksi ƠT,max= (c)
P9.037 A cantilever beam supports the loads shown. The cross-sectional dimensions of the shape are also shown....