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A block of mass m1 = 3.28 kg on a frictionless plane inclined at angle θ...

A block of mass m1 = 3.28 kg on a frictionless plane inclined at angle θ = 31.8° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.74 kg hanging vertically (see the figure). (a) What is the acceleration of the hanging block (choose the positive direction down)? (b) What is the tension in the cord?

Answered (a) which is 1.65 but cant get (b). Its not 27.6.

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Answer #1

The net force acting on the block of mass m, is, ma-T-mg sin6 The net force acting on the block of mass m, is, From above two equations it can be written as follows: m,a=(mg-m-a)-mgsin θ a(m, +m,)-g(m,-m, sin e) g(m,-n, sin θ) m + m2 9.8m/s )(2.74kg -(3.28kg)sin (31.8°) (3.28 kg + 2.74kg) 1.65 m/s2 The tension in the cord can be calculated using the expression, T (2.74kg) (9.8m/s)-(2.74kg)(1.65m/s* - 22.3N

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