How much work is associated with the expansion of a gas from 1.75 2 to 3.81...

Question

Question

Answer 1

Answer #1

Work is done by the system as gas is expanding against a pressure of 2.48 atm. 1 atm = 101325 Pa and 1 L = 0.001 m^3.

Work done by system is taken positive. W = P (V2 - V1)

W = (2.48 x 101325 Pa) x (3.81 - 1.75 ) x 0.001 m^3

W = 517.6 J ~ 516 J work was done by system (approximately)

Or we can say -516 J work was done on the system

Option (c) is the appropriate answer

Answer 2

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