Let W1=Mass of soil+can before placing in Oven=52.20g
Let W2=Mass of soil+can after removal from Oven=41.52g
Let W3=Mass of Can=22.40g
Now,
weight of wet soil W4=W1-W3=52.20-22.40=29.8g
weight of dry soil W5=W2-W3=41.52-22.40=19.12g
LIquid limit i.e, moisture content =(W4-W5)/W5
=(29.80-19.12)/19.12
0.558
liquid limit i.e, Percentage of Moisture Content =56%
COPILULILL. 4.29 A liquid limit test has been performed on a soil using the Casagrande cup....
Soils Mechanics
Assignment 3 1. In a liquid limit test on a fine-grained soil, using the Casagrande apparatus, the following results were recorded: Test # 2 Number of blows 40 30 23 Container number c19 c10 c20 Wet soil + container 93.49 92.5 92.3 87.5 Dry soil + container 90.76 90.53 89.36 85.95 Container mass 84.16 86.1 83.12 82.79 dry soil moisture loss Moisture content, w% If the plastic limit on the same soil was found to be 25% determine...
In a liquid limit test on a fine-grained soil, using the Casagrande apparatus, the following results were recorded:Test #1234Number of blows50362415Container numberJ11F12C20C2Wet soil + container90929191Dry soil + container79828387Container mass82.0081.0083.0082.00dry soilmoisture lossMoisture content, w%If the plastic limit on the same soil was found to be 25%, determine the liquid limit and plasticity index of the soil.Fill the table and draw the graph in a blank sheet and upload it in the next box
3. For a given soil, a liquid limit test results are given bellow. Number of blows, N 20 Moisture Content (%) 24.1 22.4 21.7 21.3 29 34 a. Determine the liquid limit (LL) of the soil b. Determine the flow index c. If PI = 6.7, determine the plastic limit (PL) of the soil d. The soil moisture content Win situ = 24.8% calculate the liquidity index of the soil.
QUESTION 2 A sand cone test has been performed in a recently compacted fill. The test results obtained are as follows: Initial weight of sand cone + sand = 12.51 lb Final weight of sand cone + sand = 3.26 Weight of sand to fill cone = 1.12 lb Weight of soil from hole + bucket =11.42 lb Weight of bucket =0.21 lb Moisture content test: Mass of empty moisture content can = 18.11g Mass of moist soil + can...
15. Which of the following is an Atterberg limit? Liquid limit Plastic limit Shrinkage limit All of the above 16. Effective size of soil particles is denoted by (a) D10. (b) D20. (c) D30. (d) D60. 17. A given volume of soil in natural occurrence consists of (a) solid particles only. (b) void spaces occupied by air and/or water. (c) solid particles and void spaces. (d) solid particles and void spaces occupied by air and/or water 18. Which of the...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...