In the figure below, two identical springs of spring constant 7500 N/m are attached to a block of mass 0.300 kg. What is the frequency of oscillation on the frictionless floor? Give your answer in Hz
In this case spring are in parelellel with respect to block
hence Keffective = 2k
f = 1/2π (√(2k/m)
= 1/2π(√(2×7500/0.300)
= 35.59 Hz
In the figure below, two identical springs of spring constant 7500 N/m are attached to a...
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