Q.34: Since energy of product B is less than that of the
reactant A, energy is released. Hence this is an exothermic
reaction and H < 0.
Since heat is released and n(g) is 0,
S is also less
than 0.
Since H < 0 and
S < 0, K>1
at low temperature and K <1 at high temperature.
Hence option (d) should be correct.
#35: ln(K) = ( - H / R)*(1/T) +
S / R
For the given graph, slope = - H / R > 0
=> H < 0
Hence H for the
reaction is negative.
Also Y-intercept, C = S / R > 0
=> S > 0
Hence S is
positive.
Since K is inversely proportional to T, K decreases with increase in temperature.
Since S is positive and
H is negative,
G is negative for
any temperature.
Hence G for the
reaction decreases with temperature. Hence
Hence (A), (B) and (D) are correct
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