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Problem 10 For a 2 step consecutive reaction: k: The concentration of B, [B], as a function of time was derived to be: [B] = (k2-k1) a. Show that the time when the maximum value of [B] occurs is: tmax = (ka-ki) Ln (k2 b. If ki = 0.100 s., and k2 = 0.0500 s., how much time (in s) does it take for [B] to reach its maximum value?
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