Genes A and B are located 10cM from each other on a chromosome. Gene C is...
Genes A and B are located 10cM from each other on a chromosome. Gene C is located 25cM from gene A and 15cM from gene B. Assuming that I = 0, what is the probability that the trihybrid ABC/abc will produce an ABC gamete?
Genes A and B are located 10cM from each other on a chromosome. Gene C is located 25cM from gene A and 15cM from gene B. Assuming that I = 0, what is the probability that the trihybrid ABC/abc will produce an ABC gamete?
| 38.25% | |
| 25% | |
| 1.5% | |
| 76.5% | |
|
.75% Please include explanation! |
Homework Answers
Distance between genes A and B = 15 cM
Distance between genes B and C = 10 cM
The probability recombination
Probability of SCO - DCO = 0.25 - 0.015 = 0.235
Probability of non- recombinants = 1 - 0.235 = 0.765
Half of the non recombinants are ABC and the other half are abc. Therefore, the probability that an ABC gamete is produced is 0.5 X 0.765 = 0.3825 or 38.25%
Therefore, the probability of producing ABC gamete is 38.25%
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