The plot shows the position versus time of a mass of 1.2 kg on a spring. What is the spring constant?
Can you show work please?
Homework Answers
from the graph
time period of Oscillations, T = 20/2
= 10 s
so, angular frequency, w = 2*pi/T
= 2*pi/10
= 0.6283 rad/s
given m = 1.2 kg
let k is the spring constant
we know, w = sqrt(k/m)
w^2 = k/m
==> k = m*w^2
= 1.2*0.6283^2
= 0.474 N/m <<<<<<<------------------Answer
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