Question

Prelab 3: The following circuit demonstrates the correct way to connect two car batteries together for the purposes of charging the bad battery. Good r1 Bad r2 Battery Battery Jumper Cables Figure 16: A single loop circuit illustrating the correct way to charge a car battery. Here we are modeling a real battery by having an ideal battery that supplies a voltage E in series with a resistance r. Real batteries have some internal resistance. In a real battery, the internal resistance r occurs simultaneously with the voltage rise E, not separately as shown in the diagram above. The jumper cables will also have some small resistance R a.) Apply Kirchhoffs Laws to this circuit to find the current in the circuit. (Hint, Use the six-step procedure given in the Background Information” section of this lab entitled Kirchhoffs Laws of Circuit Analysis.) b.) As the bad battery charges, E2 approaches E1. What happens to the current? c.) Use the current you found in Part (a) to find the voltage drops across the resistors r1, r2 and R.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Prelab 3: The following circuit demonstrates the correct way to connect two car batteries together for...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You have developed a new way to measure the internal resistance of a battery. The circuit...

    You have developed a new way to measure the internal resistance of a battery. The circuit you have created is shown below, with a non-ideal battery (EMF and internal resistance r in the red box), a constant external resistor R1-19.122, and a variable resistor R2. R2 has a resistance you can change over a wide range of values, from nearly zero to nearly infinity. In this circuit, you measure the voltage over R2, AV2. R1 is used to avoid damaging...

  • An old car battery that has an emf of elementof_1 = 11.6 V and an internal...

    An old car battery that has an emf of elementof_1 = 11.6 V and an internal resistance of 40.0 mohm is connected to an R = 2.00 ohm resistor. In an attempt to recharge the battery, you connect a second battery that has an emf of elementof_2 = 12.6 V and an internal resistance of 10.0 mohm in parallel with the first battery and the resistor with a pair of jumper cables. Draw a diagram of the circuit. Choose File...

  • Apply the following questions to both the circuit shown in Figure (a) (resistors in series) and...

    Apply the following questions to both the circuit shown in Figure (a) (resistors in series) and the circuit shown in Figure (b) (resistors in parallel). (a) Use Ohm's law with Kirchhoff's current and voltage laws to derive equations for currents i1, i2 and i (through Resistor R1, resistor R2, and the voltage source , respectively) in terms of R1, R2, and v. (b) R1 and R2 can be interchanged with an equivalent resistor rith resistance R without changing the values...

  • in the circuit in the figure below, the batteries have negligible internal resistance. (Take R1 2.25...

    in the circuit in the figure below, the batteries have negligible internal resistance. (Take R1 2.25 Ω. R2-4.50 Ω, and R.-6.80 .) 120 V R, 12.0 V (a) Find the magnitude of the current in each resistor 12.25Ω = 14.son = 6.80n = (b) Find the magnitude of the potential difference between points a and b (c) Find the power supplied by each battery. left battery right battery eBook

  • A circuit is constructed with five resistors and one real battery as shown above right. We...

    A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 22 Ω, R4 = R5 = 82 Ω and R2 = 147 Ω. The measured voltage across the terminals of the batery is Vbattery = 11.6 V. A circuit is constructed...

  • QUESTION 5 Consider the circuit diagram below. Choose the correct answers about the circuit below. More...

    QUESTION 5 Consider the circuit diagram below. Choose the correct answers about the circuit below. More than one may be correct. R2 = 5760 W R576 w А R = 576 120 V The equivalent resistance of the circuit is 864 Ohms. The voltage across the resistor R1 moving clockwise from the positive side of the battery is equal to the voltage across the parallel combination of R2 and R3, 60 V. The current supplied by the battery is 0.14...

  • Circuit with Two Batteries and Six Resistors 1 2 3 4 5 6 A circuit is...

    Circuit with Two Batteries and Six Resistors 1 2 3 4 5 6 A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 18 V and V2 12 V. The I,I I, R positive terminals are indicated witha+ R Sp. R5 sign, The values for the resistors are: R1 = Rs 74 Ω, R2-R6-86 Ω R3-103 Ω, and ,a. VI R4 135 Q. The positive directions for the R4 currents l1, 12 and...

  • Kirchhoff's Laws Consider the circuit below. Assume the internal resistance of each battery is r =...

    Kirchhoff's Laws Consider the circuit below. Assume the internal resistance of each battery is r = 1.90 12. Also assume, that R1 = 12.5 2, R2 = 10.6 2, R3 = 9.00 2, R4 = 15.0 2, R5 = 18.2 2, E1 = 15.0 V, E2 = 15.0 V and E3 = 9.00 V. Calculate the current 13. ho 0.24A Submit Answer Incorrect. Tries 1/40 Previous Tries Calculate the current I2. 0.68mA Submit Answer Incorrect. Tries 2/40 Previous Tries Calculate...

  • 2. The circuit diagram shown in Figure 2 shows two emf sources (batteries) connected together through...

    2. The circuit diagram shown in Figure 2 shows two emf sources (batteries) connected together through a conductor with resistance R- 0.2 S2 in order to form a battery pack. The batery pack, is then connected to a light bulb having a resistance of Rb-55 ?. The sour internal resistance ri 0.025 ? and r2-0.020 ? as shown in Figure to the right. a. [5 marks! If ?? = 13.0 V and ?,-1 1.5 V, calculate the current 12 ri...

  • Constants The batteries shown in the circuit in the figure have zero internal resistances and emf...

    Constants The batteries shown in the circuit in the figure have zero internal resistances and emf values Ej = 12.0 V and E2 = 15.8 V, respectively. The resistors have resistances R1 =7.40 and R2 = 10.8 0. R www & R & Part A Find the current through resistor Ri. ΑΣΦ D. SH ? I = A Submit Request Answer Part B Find the current through resistor R2. IVO ALO ? 11 A Submit Request Answer Part C Find...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT