Question

Combining 0.389 mol of Fe2O3 with excess carbon produced 14.6g of Fe. a. What is the actual yield of iron in moles? b. What is the theoretical yield of iron in moles? c. What is the percent yield?

Answer 1

The chemical reaction taking place is:

2 Fe2O3 + 3 C —> 4 Fe + 3 CO2

a)

actual yield mass = 14.6 g

molar mass of Fe = 55.85 g/mol

actual yield mol = mass/molar mass

= 0.261 mol

Answer: 0.261 mol

b)

from reaction above:

2 mol of Fe2O3 gives 4 moles of Fe

moles of Fe theoretically = 2*moles of Fe2O3

= 2*0.389 mol

= 0.778 mol

Answer: 0.778 mol

c)

% yield = actual * 100 / theoretical

= 0.261*100/0.778

= 33.5 %

Answer: 33.5 %