SOLUTION :
AC = 2 BD and Area ABCD = 100 in^2
Let diagonal BD = 2x
So, diagonal AC = 4x
Diagonals are perpendicular to each other.
So, Area of ABCD
= 2 * Area of triangle ABC
= 2 * (1/2 * base * height)
= base * height (of triangle ABC)
= 4x * x
= 4x^2
So,
4x^2 = 100 in^2 (given area of ABCD)
=> x = sqrt(100/4) = 5 in.
So,
AC = 4x = 4*5 = 20 in. (ANSWER)
BD = 2x = 2*5 = 10 in (ANSWER)
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