According to Henderson Hassselbatch Equation
pH= pKa + log [dissociated]/[undissociated]
Ka = 2.9 X 10 ^-8
for pKa = - log (Ka)
= -log 2.9 X 10 ^-8
= 7.53
conc of dissociated =0.099 mol L-1
conc of undissociated =0.158 mol L-1
log [dissociated]/[undissociated] = -0.203
Putting in , pH= pKa + log [dissociated]/[undissociated]
=7.53 -0.203
= 7.327
Calculate the pH of a buffer that is 0.158 mol ["HClO and 0.099 mol L"Nacio. The...
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