Question

Calculate the pH of a buffer that is 0.158 mol [HClO and 0.099 mol LNacio. The Ka for HCIO is 2.9 x 10-8 Select one: a. 6.6
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Answer #1

According to Henderson Hassselbatch Equation

pH= pKa + log [dissociated]/[undissociated]

Ka = 2.9 X 10 ^-8

for pKa = - log (Ka)

= -log 2.9 X 10 ^-8

= 7.53

conc of dissociated =0.099 mol L-1

conc of undissociated =0.158 mol L-1

log [dissociated]/[undissociated] = -0.203

Putting in , pH= pKa + log [dissociated]/[undissociated]

=7.53 -0.203

= 7.327

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