In R Studio, Does the number of tadpoles vary between the relative altitudes at which the sites were located? If so, which of the altitude level means are significantly different?
Site | Rain | Temp | Altitude | Tadpoles | Breeding |
1 | 769.77 | 22.37 | Low | 97 | 61 |
2 | 664.85 | 19.46 | Low | 86 | 70 |
3 | 807.13 | 23.17 | Low | 104 | 61 |
4 | 620.05 | 17.85 | Low | 117 | 113 |
5 | 673.21 | 20.29 | Low | 98 | 92 |
solution:
Here the statistical hypothesis to be tested is as follows,
Null hypothesis: μ = 48
Alternative hypothesis: μ ≠ 48
Where, μ = mean number of breeding ponds ,
R - code is as follows;
Mu= 48 # True or given mean
Breeding=c(61,70,61,113,92,100,102,66,64,18)
Xbar= mean(Breeding) # sample mean
Xbar
SE=sd(Breeding) # Sample standard deviation/ standard error
SE
# Here test statistic computed as follows,
Tcal= (Xbar- Mu)/SE
Tcal
Ttab=qt(0.975,9) # Tabulated value of t-probability distribution at
9 d.f. and 95% level of significance.
Ttab
# Since Tcal < Ttab , we may accept null hypothesis.
R-code out put ;-
> Mu= 48 # True or given mean > Breeding=c(61,70,61,113,92,100,102,66,64,18) > Xbar= mean(Breeding) # sample mean > Xbar [1] 74.7 > SE=sd(Breeding) # Sample standard deviation/ standard error > SE [1] 27.79708 > > # Here test statistic computed as follows, > > Tcal= (Xbar- Mu)/SE > Tcal [1] 0.9605325 > Ttab=qt(0.975,9) # Tabulated value of t-probability distribution at 9 d.f. and 95% level of significance. > Ttab [1] 2.262157 > > # Since Tcal < Ttab , we may accept null hypothesis.
Hence we may claim that the mean number of breeding ponds found in NSW is same as the mean number found in the Victorian surveys.
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In R Studio, Does the number of tadpoles vary between the relative altitudes at which the...
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