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Three samples of crystalline materials are available: sample A, B, and C. All of them are...

Three samples of crystalline materials are available: sample A, B, and C. All of them are melted exactly at 82 degrees Celsius. Combine a mixture of sample A and B and melt at 82-degree Celsius. Next, combine a mixture of sample A and sample C and melt at 64-degree Celsius. Finally. Combine a mixture of sample B and sample C and melt at 71-degree Celsius. What can you determine about the samples A, B, and c?

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Answer #1
  • With material C common with A the melting point in combine of A + C is lowest of all the given combinations.
  • When B is added to C avoiding A it went up again more than 64-degree Celsius i.e 71-degree Celsius
  • The melting point of C is lesser than the melting points of B and A
  • The melting point of combination of A + B > B + C > A + C from which it cab understood B is greater than both A and C
  • A + B > B + C means that A > C
  • so the melting points of the given materials can be stated as B > A > C
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