In a random sample of 18 senior-level chemical engineers, the mean annual earnings was 128000 and the standard deviation was 35440. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers
1. critical value
2. standard error of the sample mean
3. margin of error
4. lower limit of the interval
5. upper limit of the interval
In a random sample of 18 senior-level chemical engineers, the mean annual earnings was 128000 and...
In a random sample of 16 senior-level chemical engineers, the mean annual earnings was 120250 and the standard deviation was 34700. Assume the annual earnings are normally distributed and construct a 95% confidence interval for the population mean annual earnings for senior-level chemical engineers. 1. The critical value: 2. The standard error of the sample mean: 3. The margin of error: 4. The lower limit of the interval: 5. The upper limit of the interval:
The annual earnings of 12 randomly selected computer software engineers have a sample standard deviation of $ 3626 Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squared σ2 and the population standard deviation sigma σ. Use a 95% level of confidence. Interpret the results. What is the confidence interval for the population variance sigma squared σ2? What is the confidence interval for the population standard deviation sigma σ? Please show...
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.4, and the sample standard deviation, s, is found to be 4.9. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about if the sample size, n, is 35. Lower bound: :Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the sample size,...
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)
A simple random sample of size n is drawn. The sample mean,x overbarx, is found to be 17.8 and the sample standard deviation, s, is found to be 4.4 (a) Construct a 95% confidence interval about μ if the sample size, n, is 35 Lower bound: ____ Upper bound: ______ (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about μ if the sample size, n, is 51 Lower bound: ____ Upper bound:...
A simple random sample of size n is drawn. The sample mean, , is found to be 19.2, and the sample standard deviation, s, is found to be 4.6. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 35. Lower bound: I; Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about u if...
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.2, and the sample standard deviation, s, is found to be 4.9. Click the icon to view the table of areas under the t-distribution (a) Construct a 95% confidence interval about ju if the sample size, n, is 34. Lower bound: upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about u if the...
A simple random sample of size n is drawn. The sample mean, X, is found to be 17.9, and the sample standard deviation, s, is found to be 4.8. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about us if the sample size, n, is 34. Lower bound: upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about if the sample...
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.4, and the sample standard deviation, s, is found to be 4.9. Click the icon to view the table of areas under the t-distribution. OC. The margin of error decreases. (c) Construct a 99% confidence interval about if the sample size, n, is 35. Lower bound: 17.14; Upper bound: 21.66 (Use ascending order. Round to two decimal places as needed.) Compare the results...
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for the population mean. Assume that your data is normally distributed and σ is unknown. Include a statement that correctly interprets the confidence interval in context of the scenario. Calculations/Values Formulas/Answers Mean 72,224.34 Standard Deviation 22,644.46 n 364 Critical Value Margin of Error Lower Limit Upper Limit Question 3 construct a 99% confidence interval for the population mean. Assume that your data is normally distributed...