The following MIPS assembly code contains a mistake that violates the MIPS convention in terms of...
- The following MIPS assembly code contains a mistake that violates the MIPS convention in terms of using stack for storing/protecting registers.
- What is the mistake and how should it be fixed? Correct the corresponding lines in the code.
- For the corrected code, sketch the stack frame contents at the time when the instruction ‘move $s1, $a1’ is being executed.
f: addi $sp, $sp, 12
sw $ra, 8($sp)
sw $s1, 4($sp)
sw $s0, 0($sp)
move $s0, $a0
move $s1, $a1 # Stack frame?
jal g
add $v0, $v0, $s0
lw $ra, 8($sp)
lw $s1, 4($sp)
lw $s0, 0($sp)
addi $sp, $sp, -12
jr $ra
g: mul $v0, $s0, $s1
jr $ra
Homework Answers
Below shows the changed code with explanation
f:
#Stack always grow from frame pointer to
bottom
addi
$sp,$sp,-12
sw $ra,8($sp)
sw $s1,4($sp)
sw $s0,0($sp)
#Before function call passing arguments will be
a0-a3 registers
move $a0,$s0
move $a1,$s1
jal g
add $v0,$v0,$s0
lw $ra,8($sp)
lw $s1,4($sp)
lw $s0,0($sp)
#Free the aloocated space
addi $sp,$sp,12
jr $ra
#Function gets parameters value from a0 and a1
#Return result from v0
g:
mul $v0,$a0,$a1
jr
$ra
---------------------------------------------------------
Stack frame
Add Answer to:
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Starting code:
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