A random sample of 45 adult elephants had the sample mean weight of 12,240 pounds and...
A random sample of 45 adult elephants had the sample mean weight of 12,240 pounds and the sample standard deviation of 450 pounds. A random sample of 80 adult hippos had the sample mean weight of 5,700 pounds and the sample standard deviation of 400 pounds. Assume that the two populations are approximately normally distributed. A zoologist claims that the difference between the overall weights of adult elephants and adult hippos is 6,300 pounds, however others believe the difference must be higher. Test the claim at a 1% level of significance.
Homework Answers
Add Answer to:
A random sample of 45 adult elephants had the sample mean weight
of 12,240 pounds and...
A sample of 8 adult elephants had an average weight of 12,300 pounds. The standard deviation...
A sample of 8 adult elephants had an average weight of 12,300 pounds. The standard deviation for the sample was 22 pounds. Find the 95% confidence interval of the population mean for the weights of adult elephants.
A sample of 25 adult elephants had a mean weight of 9500 pounds with a sample...
A sample of 25 adult elephants had a mean weight of 9500 pounds with a sample standard deviation of 150 pounds. The population distribution is normal. The margin of error for 99% confidence interval calculation is equal to: a, 61.9 b. 77.3 c. 83.9 The 99% confidence interval for the population mean is equal to: a, (9416.1, 9583.9) b. (9422.7, 9577.3) c. (8438.1, 9561.9)
It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder...
It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder claims that the average weight of an adult male Labrador retriever is not equal to 70 pounds. A random sample of 45 male Labradors weigh an average of 73.6 pounds with a standard deviation of 15.1 pounds. Test the breeder's claim at a = 0.01. Part a: State the null and alternate hypothesis. Part b: Sketch, label and shade the rejection region. Part c:...
Exercise 6. Weights. For a random sample of 38 students, the mean weight, x¯ = 176.8...
Exercise 6. Weights. For a random sample of 38 students, the mean weight, x¯ = 176.8 pounds. Assume that σ = 6.4 pounds and α = 0.05. A researcher claims that the population mean weight is greater than 175 pounds. Is there enough evidence to support the researcher’s claim? Assume the population is normally distributed.
In a random sample of 23 fifth graders, the mean weight is 62.8 pounds and the...
In a random sample of 23 fifth graders, the mean weight is 62.8 pounds and the standard deviation is 7.9 pounds. Estimate the mean weight of all fifth graders using a 99% C.I. 8 Ans 8 From the time of diagnosis, a random sample of 120 liver cancer 9. patients has a mean life expectancy of 6 months with a standord deviation of .35 months. Estimate the mean life expectancy for all liver cancer patients using a 94% C.I. Ans...
Dog weights. Adult German shepherd weights are normally distributed with mean of 73 pounds and standard...
Dog weights. Adult German shepherd weights are normally distributed with mean of 73 pounds and standard deviation of 10 pounds. (a) The bottom 21% of weights are below what weight? (b) 79% of weights are above what weight? (c) The top 21% of weights are above what weight? (Round answers to one decimal place)
In a random sample of 64 trout, the average weight is 3 pounds, with standard deviation...
In a random sample of 64 trout, the average weight is 3 pounds, with standard deviation s = .5 pounds Find: sample mean standard error of the sample mean margin of error 95% 95% confidence interval for the population mean, µ:
a random sample of 25 people whose population average weight is 160 pounds with a standard...
a random sample of 25 people whose population average weight is 160 pounds with a standard deviation of 20 pounds would have a standard deviation of the sample mean equal to ? What is the mean of the sampling distribution referred to in question 4?
the mean weight of all 20 year old women is 128 pounds. a random sample of...
the mean weight of all 20 year old women is 128 pounds. a random sample of 40 vegetarian 20 year old women resulted in a sample mean of 122 pounds and standard deviation of 15 pounds. do vegetarian 20 year old women weigh significantly less than 20 year women in general? a). set up hypothesis for test b.)calculate 99% confidence interval for population mean weight of all 20 year old vegetarian women. what test could you use to solve this...
The distribution of weight measurements of adult women in Neverland is approximately Normal with mean 166...
The distribution of weight measurements of adult women in Neverland is approximately Normal with mean 166 pounds and standard deviation 20 pounds. What percentage of the population is between 1SD and 2SD below the mean? (2p)
It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder claims that the average weight of an adult male Labrador retriever is not equal to 70 pounds. A random sample of 45 male Labradors weigh an average of 73.6 pounds with a standard deviation of 15.1 pounds. Test the breeder's claim at a = 0.01. Part a: State the null and alternate hypothesis. Part b: Sketch, label and shade the rejection region. Part c:...
In a random sample of 23 fifth graders, the mean weight is 62.8 pounds and the standard deviation is 7.9 pounds. Estimate the mean weight of all fifth graders using a 99% C.I. 8 Ans 8 From the time of diagnosis, a random sample of 120 liver cancer 9. patients has a mean life expectancy of 6 months with a standord deviation of .35 months. Estimate the mean life expectancy for all liver cancer patients using a 94% C.I. Ans...
Dog weights. Adult German shepherd weights are normally distributed with mean of 73 pounds and standard deviation of 10 pounds. (a) The bottom 21% of weights are below what weight? (b) 79% of weights are above what weight? (c) The top 21% of weights are above what weight? (Round answers to one decimal place)
Most questions answered within 3 hours.
-
How are the activators and repressors different in eukaryotes vs
prokaryotes for regulation of gene expression?
asked 9 minutes ago -
Task 2.6 : In this exercise, you will create a script to
echo users, based on...
asked 8 minutes ago -
The diameter of the Sun is 1.4x 106 kilometers. (1 km
= 3280 ft) What is...
asked 12 minutes ago -
Calculate the value of the translational partition function of
O2 at 300 K for a volume...
asked 28 minutes ago -
Consider the following tasks, times, and predecessors for an
assembly of set top cable converter boxes:...
asked 27 minutes ago -
10.________ is the proportion of variance in the dependent
variable that is accounted for by the...
asked 40 minutes ago -
Find at least three implicit modelling assumptions or other
qualitative factors which are relevant but not...
asked 41 minutes ago -
Write a method that determines the key of the successor of the
root node in a...
asked 55 minutes ago -
Determine the lattice energy (in kJ/mol) of NaF(s),
using the data provided.
Energy to sublime Na(s)...
asked 1 hour ago -
How do you explain the deviations from Hardy-Weinberg
equilibrium in a population where smoking has effected...
asked 1 hour ago -
As a general rule, testing should be conducted until all bugs
have been detected.
A. True....
asked 1 hour ago -
Just before a referendum on a school budget, a local newspaper
polls
436
voters to predict...
asked 1 hour ago