suppose a planet has an atmosphere of pure ammonia at 1.5 celsius. what is the vrms...
Homework Answers
Temperature in kelvin is = 273+1.5
= 274.5 K
It is given that molecular weight of ammonia = 17.03 g/mol
Convert the molecular weight into kg/mol = 17.03×10-3 kg/mol
Root mean square velocity is, vrms = square root ( 3RT /M)
Here, R is the universal gas constant, T is the temperature in kelvin and M is the molecular weight.
vrms = square root(3×8.314×274.5/17.03×10-3)
= 634.058 m/sec
The RMS speed of ammonia is = 634.058 m/sec
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