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Suppose that the average velocity (vrms) of carbon dioxide molecules (molecular mass is equal to 44.0...

Suppose that the average velocity (vrms) of carbon dioxide molecules (molecular mass is equal to 44.0 g/mol) in a flame is found to be 9.39 ✕ 102 m/s. What temperature in kelvin does this represent?

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Answer #1

Use equation for rms speed of a molecule to find the required temperature as shown below***************************************************************************************************
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