A uniform rod of mass m= 6kg has length L= 30 cm. we pivoted it at...
A uniform rod of mass m= 6kg has length L= 30 cm. we pivoted it at L/6 from the end. We now set the rod into small angle oscillations. what is the angular frequency w of the oscillation given that the moment of inertia about the pivot is 7/36 mL^2
A) square root 2/3 g/L
b) square root 12/7 g/L
c) square root 9/7 g/L
d) square root 3/2 g/l
e) square root 3/7 g/L
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A uniform rod of mass m= 6kg has length L= 30 cm. we pivoted it
at...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is ml2/9? L/3 Pivot L С.М. 2L/3
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it...
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure. We now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is mL2/9? L/3 Pivot L с.м. 2L/3
A uniform rod of mass M and length L=1.6 m is pivoted about one end and...
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A compound pendulum is made up of a rod of length L, with mass M and a solid sphere of radius r, with mass m (see figure below). The pendulum is pivoted about one end and released from rest from and angle of 0, (angle with the vertical). (a) Find the distance, dom, of center of mass of this pendulum from its pivot. (b) Draw a free body diagram and write down Newton's 2nd Law (for rotation) for the pendulum...
Hi, please answer the question. I will be more then happy to thumbs up it if...
Hi, please answer the
question. I will be more then happy to thumbs up it if it is
correct!
A uniform rod of mass m = 10 kg has length L = 65 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot...
iz ML?.ro If a thin rod with mass M and length L is pivoted at the...
iz ML?.ro If a thin rod with mass M and length L is pivoted at the center of mass and free to rotate. At this condition the moment of inertia of the thin rod is ICM = If the 12 same rod is pivoted L/6 away from its center of mass the new moment of inertia of the rod is INEW. What is the ratio of INEW/ICM? Round of your answer to two decimal places
11. A uniform thin rod of length L and mass M, pivoted at one end as...
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A thin uniform rod (length = 1.77 m, mass = 3.13 kg) is pivoted about a...
A thin uniform rod (length = 1.77 m, mass = 3.13 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 58.5° below the horizontal. What is the angular acceleration of the rod at the instant it is released? (in rad/s^2) A: 2.712 B: 3.173 C: 3.713 D: 4.344 E: 5.082 F: 5.946 G: 6.957 H: 8.140
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is ml2/9? L/3 Pivot L С.М. 2L/3
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure. We now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is mL2/9? L/3 Pivot L с.м. 2L/3
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Suppose the pivot is located at a small hole drilled in the rod at a distance L/4 from the upper end. What is the period of oscillation of the rod when it is hung from this pivot point and swings through small oscillations? Pivot Mg
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillation if the amplitude of the motion is small. Pivot Mg
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A compound pendulum is made up of a rod of length L, with mass M and a solid sphere of radius r, with mass m (see figure below). The pendulum is pivoted about one end and released from rest from and angle of 0, (angle with the vertical). (a) Find the distance, dom, of center of mass of this pendulum from its pivot. (b) Draw a free body diagram and write down Newton's 2nd Law (for rotation) for the pendulum...
Hi, please answer the
question. I will be more then happy to thumbs up it if it is
correct!
A uniform rod of mass m = 10 kg has length L = 65 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot...
iz ML?.ro If a thin rod with mass M and length L is pivoted at the center of mass and free to rotate. At this condition the moment of inertia of the thin rod is ICM = If the 12 same rod is pivoted L/6 away from its center of mass the new moment of inertia of the rod is INEW. What is the ratio of INEW/ICM? Round of your answer to two decimal places
11. A uniform thin rod of length L and mass M, pivoted at one end as shown above, is held horizontal and then released from rest. Ignore all effects due to friction. (a) Find the angular speed of the rod as it sweeps through the vertical position. solution: 、13g / L (b) Find the force exerted on the rod by the pivot at this instant. solution Mg (c) Starting from the horizontal position, what initial angular speed would be needed...
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