Not all gases follow ideal behaviour. There are internuclear forces of attraction which make gases deviate from ideal behaviour.
Pressure is calculated as the net force exerted by gas on an area(wall of the container). Now real gases have inter nuclear force of attraction which reduce this net force exerted on wall of container. Hence less pressure is observed for a real gases than ideal gases and we say that gases are in attractive region.
Similarly opposite is true when gases are in repulsive region. Such real gases exert more pressure on the wall of container than real gases.
real gases behave similarly to ideal gas when the internuclear forces are negligible(whether attractive or repulsive).Hence pressure calculated will be same.
ideal gases assume that the volume occupied by atoms is negligible but real gases have actual volume occupied by atoms and this difference is called volume correction factor 'b'. this factor depends on size of the atom and not on forces of interaction(attractive or repulsive).
Please do not use Z in your answer as the main answer, only use it to...
A gas at 375 K and 16 atm has a molar volume 14% smaller than that calculated from the ideal gas law. Calculate the compressibility factor (Z) under these conditions and the molar volume of the gas. Are the attractive or repulsive forces dominating in the gas? Explain.
Which of the following statements is true about the compressibility factor (Z)? When Z is greater than 0, attractive forces between the particles dominates. When Z is less than 0, attractive forces between the particles dominates. Z steadily increases for an ideal gas. Z equals 24.79 L bar for an ideal gas. Repulsive forces between particles cause Z to be less than 0 at high pressures.
1 N 3 V c. When we derived the expression fact that they interact with each other. Discuss whether the pressure of a real gas for which these assumptions are not true should be larger or smaller than the pressure of the ideal gas calculated according to the derived expression. Compare an ideal gas and a real gas assuming the gases are in containers of the same volume and have the same number of particles with the same average of...
Use the van der Waals equation of state to calculate the pressure of 2.10 mol of Kr at 471 K in a 3.70L vessel. Van der Waals constants can be found in this table. Number P- 2.004 atm Use the ideal gas equation to calculate the pressure under the same conditions. Number P= 21.947 atm In a 15.5 L vessel, the pressure of 2.10 mol of Kr at 471 K is 5.24 atm when calculated using the ideal gas equation...
Use the van der Waals equation of state to calculate the pressure of 2.40 mol of H2S at 499K in a 4.60 L vessel. Van der Waals constants can be found in the van der Waals constants table. Use the ideal gas equation to calculate the pressure under the same conditions. In a 16.30 L vessel, the pressure of 2.40 mol of H2S at 499 K is 6.03 atm when calculated using the ideal gas equation and 5.97 atm when calculated using the...
Question 1 (a) Use the ideal gas equation to calculate the pressure (in atm) of 2.40 mol of krypton (Kr) at 455 K in a 4.50 L vessel. (b) In a 16.3 L vessel, the pressure of 2.40 mol of Kr at 455 K is 5.50 atm when calculated using the ideal gas equation and 5.40 atm when calculated using the van der waals equation of state (Note: a=5.121 and b = 0.0106). Why is the percent difference in the...
Explain your reasoning and show your work. Do not use any PV-diagrams. Only use the Ideal Gas Law for your solution. S8. Why is the folloruing situation impossibler An apparatus is designed so that steam initially at T-150°C, P= 1.00 atm. and V-0.500 m in a piston-cylinder apparatus under- goes a process in which (1) the volume remains constant and the pressure drops to 0.870 atm, followed by (2) an expansion in which the pressure remains constant and the volume...
Please answer & explain 22-25 22. Pressure is created when a gas is compressed and the temperature is decreased proportionally b) gas particles collide with the sides of their container more gas particles are added and the volume is increased proportionally gas particles are removed and the volume stays the same 23. because In response to Boyle's law, the pressure of a gas increases as the volume a) decreases; the gas particles strike the walls of the container more often...
please answer question 8 and 9 only Behavior of Gases: Molar Mass ofa Vapor Atmospheric pressure Atmospheric pressure Gas sample exerting pressure Graduated gas buret " Height of mercury column measures pressure on gas Mercury dingMsloM Leveling bulb d do SYTa o Rubber connecting tube mulo c Stopcock open to air; mercury at same level montal eall m 1 J sbally bateub 0 Teals AFIGURE 1 A gas buret Consider Figure 1. If the height of the mercury column in...
please answer the questions based on the reaction and the result provided for the experiment. reaction is: Mg (s) + 2HCl (aq) —-> MgCl2 (aq) +H2 (g) the first picture is the data collected for the experiment. Data: Trial O. o 344 36.00 mL 20.00 cm Trial #1 o.σ 39万 4o.81 m1 4.20 m Mass magnesiu n lume Height of wates Column (Cim) (Distance baborr wte eel wader temperature C) 22.6 22.2°c Baranetric pmesureH Post-Lab Questions (Please type your answers.)...