3. For the reaction : 2 SO2 (g) + O2 (g) ↔ 2
SO3 (g)
the value of K is 17.3 at 38 C
If the equilibrium concentration of sulfur dioxide at 38 C is found to be 0.126 M, and the equilibrium concentration of oxygen is found to be 0.0582 M, what is the equilibrium concentration of sulfur trioxide?
Consider the following equilibrium reaction : Heat + 2 SO2 (g) + O2(g) ↔ 2 SO3(g) Assume the above reaction is allowed to reach equilibrium prior to the following changes. Answer the following questions by writing increase, decrease or remain the same on the line. **please also explain why** If the reaction mixture is heated up , the value of the equilibrium constant will _______________________ If SO2 (g) is added to the reaction vessel the concentration of O2(g) will____________________________. If SO3 (g) is...
Sulfur trioxide is made from the oxidation of sulfur dioxide. 2 SO2 + O2 --> 2 SO3. A 16 g sample of SO2, reacted with excess oxygen, gives 18 g SO3. What is the percent yield?
Sulfur trioxide is formed from sulfur dioxide and oxygen according to the reaction formula 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g) with the equilibrium constant 2.5 × 1010 at the temperature 5.0 × 102 K. A reaction vessel with a volume of 0.25 L contains from start 0.030 moles of SO2 (g) and 0.050 moles of O2 (g). a) Calculate the partial pressure SO3 (g) after equilibrium is reached at 5.0 × 102 K. b) Will more...
Consider the decomposition of sulfur trioxide gas into sulfur dioxide and oxygen 2SO3(g)<- ->2SO2(g) +O2(g) a flask of SO3 is filled to 0.960 M and allowed to decompose. at equilibrium the concentration of SO2 is 0.320 M what is Kc?
1.For the reaction at equilibrium 2 SO3↔ 2 SO2 + O2 (∆Horxn= 198 kJ/mol), if we increase the reaction temperature, the equilibrium will (1 point ) * No shift None of the above Question lacks sufficient information Shift to the right 2. For the equilibrium reaction 2 SO2(g) + O2(g) ↔ 2 SO3(g), ∆Horxn = -198 kJ/mol. Which one of these factors would cause the equilibrium constant to increase? (1 point ) * Add a catalyst Decrease the temperature None...
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+O2(g)→2SO3(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of sulfur dioxide, oxygen, and sulfur trioxide has the following composition: Calculate the value of the equilibrium constant Kp for this reaction. Round your answer to 2 significant digits. compound pressure at equilibrium SO2 58.3 atm 02 84.7 atm SO3 66.3 atm
Consider the following reaction: 2 H2O(g) + 2 SO2(g) ↔ 2 H2S(g) + 3 O2(g) A reaction mixture initially contains 2.8 M H2O and 2.6 M SO2. Determine the equilibrium concentration of H2S if Kc for the reaction at this temperature is 1.3 × 10-6. Consider the following reaction: 2 H2O(g) + 2 SO2(g) ↔ 2 H2S(g) + 3 O2(g) A reaction mixture initially contains 2.8 M H2O and 2.6 M SO2. Determine the equilibrium concentration of H2S if Kc...
Sulfur dioxide, SO2(g), can react with oxygen to produce sulfur trioxide, SO3(g), by the reaction 2 50, (g) + O2(g) 250, (g) The standard enthalpies of formation for SO2(g) and SO2(g) are AH (SO2(g)] = –296.8 kJ/mol AH (SO2(g)] = -395.7 kJ/mol Calculate the amount of energy in the form of heat that is produced when a volume of 1.09 L of So, (g) is converted to 1.09 L of So, (g) according to this process at a constant pressure...
Given the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g) Starting with 0.100 M of SO2 and 0.050 M of O2, which value of K should be used and why? a. KC because the chemicals are in the gas phase. b. KP because the concentrations are in Molarity. c. KP because the chemicals are in the gas phase. d. KC because the concentrations are in Molarity.
3. Consider the following reaction: 2 SO2 (g) + O2 (g) → 2 SO3 (g) AH.x = -197.6 kJ a. If 285.3 g of SO2 is allowed to react with 158.9 g of O2, what is the limiting reactant and theoretical yield of SO3 in liters if the reaction is performed at 315 K and 50.0 mmHg? How much of each reactant remains at the end of the reaction? [10] LR: SO TY: SO2 remaining: O2 remaining: Imol soa 64.000log...