Question 1
In a chi -square test of independence , the null hypothesis states that-----------.
a. the two variables of interest are related in the population.
b. the column frequencies equal the row frequencies
c. the sum of the and the column frequencies equal the total frequency
d. the two variables of interest are unrelated in the population
Question 2
A survey asked people whether they identified as a morning person, night person, or had no preference.
a. 270 replied Morning Person
b. 240 replied Night Person
c. 90 replied No Preference
If your expectation would have been an equal distribution across the 3 categories. What is the observed chi-square value?
a. 200
b.117
c. 93
d. 600
Question 3
Generally speaking, if the observed and expected results are not totally identical, the null hypothesis should be-------------.
a. rejected only if the difference cannot likely attributed to the sampling error
b. rejected
c. accepted only if the experiment is repeated
d. accepted
Answer - 1:
In a chi -square test of independence , the null hypothesis states that-----------.
d. the two variables of interest are unrelated in the population
Answer - 2: Observed value = 93
Option C is correct.
Answer - 3: Generally speaking, if the observed and expected results are not totally identical, the null hypothesis should be-------------.
a. rejected only if the difference cannot likely attributed to the sampling error
Question 1 In a chi -square test of independence , the null hypothesis states that-----------. a....
QUESTION 58 The chi-square test of independence does not allow us to state that one variable causes a change in another variable when the null hypothesis is rejected. True False QUESTION 59 When performing a hypothesis test to compare two or more population proportions, the expected frequencies must always be integer values. True False QUESTION 60
Which of the following could be a null hypothesis for a chi-square goodness-of-fit test? a. The means increase evenly across categories. b. The dependent variable is normally distributed. c. The variances are equal across categories. d. The frequencies in each category are equal
The null hypothesis for a chi-square contingency test of independence for two variables always assumes that the variables are independent.AnswerTrueFalse
Which step should be taken next if the null hypothesis is rejected in a chi-square test? OA. O B. Create confidence intervals to estimate the differences. Examine the standardized residuals to understand the pattern C. Check that the conditions are satisfied. D. Plot the data on a chart to understand the pattern. Which of the following is NOT one of the tests discussed in Chapter 16? A Chi-square test for independence B. Chi-square goodness-of-fit test OC. CH-square test for contingency...
When we carry out a chi-square goodness-of-fit test for a normal distribution, the null hypothesis states that the population: a) does not have a normal distribution. b) has a normal distribution. c) has a chi-square distribution. d) does not have a chi-square distribution. e) has k − 3 degrees of freedom.
3. The chi-square test for goodness of fit- No preference Aa Aa A developmental psychologist is studying bonding between healthy newborn bables and immediate family members. He wants to know if mothers use smell to recognize their one-week-old infants. To investigate, he selects a randonm sample of mothers of one-week-old infants. Each mother is presented with a garment worn by her infant and two garments wom by unrelated babies. He asks each of the mothers to identify her infant's garment....
In performing a chi-square test of independence, as the differences between respective observed and expected frequencies _________, the probability of concluding that the row variable is independent of the column variable increases. A. stay the same B. decrease C. increase D. double
Q1) The null hypothesis in a chi square analysis states that the predicted values significantly differ from the observed values. (True or false) Q2) In laboratory 4, the chi square test will be used to assess the genetic linkage between the gray and tan loci in Sordaria fimicola. (True or false)
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data). Response Male Female Total Not at all 23 25 48 Somewhat 13 22 35 Very 26 16 42...
If I reject the null hypothesis of a Chi-Square Goodness-of-Fit Test, which of the following statement best summarizes my conclusion? There is sufficient evidence to conclude that the two variables are independent. There is sufficient evidence to conclude that the two variables are associated. There is not sufficient evidence to conclude that my proposed distribution does not fit the population. There is sufficient evidence to conclude that my proposed distribution does not fit the population.