Question

Calculate the required mass of an unknown nonelectrolyte (ℳ = 168.0568 g/mol) dissolved in 133.9 g...

Calculate the required mass of an unknown nonelectrolyte (ℳ = 168.0568 g/mol) dissolved in 133.9 g of solvent that gives a solution that boils at 60.35 °C. The boiling point of the pure solvent is 53.89 °C and its Kb value is 4.40 °C/m. Report your answer to TWO places past the decimal.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Calculate the required mass of an unknown nonelectrolyte (ℳ = 168.0568 g/mol) dissolved in 133.9 g...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved...

    3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...

  • 1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g...

    1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...

  • 3a. Calculate the required mass of an unknown nonelectrolyte (ℳ = 125.7998 g/mol) dissolved in 12...

    3a. Calculate the required mass of an unknown nonelectrolyte (ℳ = 125.7998 g/mol) dissolved in 129.7 g of solvent that gives a solution that freezes at 1.85 °C. The freezing point of the pure solvent is 4.44 °C and its Kf value is 1.87 °C/m. Report your answer to TWO places past the decimal. 3b. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.613 g dissolved in 250.3 mL of water at 19.47 °C has an osmotic...

  • 2a Calculate the freezing point of a solution that is made from 39.9 g of a...

    2a Calculate the freezing point of a solution that is made from 39.9 g of a nonelectrolyte (ℳ = 142.4701 g/mol) dissolved in 186.3 g of solvent. The solvent freezes at 1.24 °C and its Kf value is 2.09 °C/m. Report your answer to TWO places past the decimal. 2b The solubility of carbon dioxide gas at 37.3 °C and a carbon dioxide pressure of 554 mmHg is 4.04 × 10−3 g/L. What is the Henry's Law constant in mol⋅L−1⋅atm−1?...

  • Instructor: Dr. Anna Toy-pal 8. (15 pts) A solution contains a 0.250 g of an unknown...

    Instructor: Dr. Anna Toy-pal 8. (15 pts) A solution contains a 0.250 g of an unknown nonvolatile nonelectrolyte dissolved in 40.0 g of CCl, as the solvent. The boiling point of the solution was 0.357 °C higher than that of the pure solvent. Given Ks - 5.02 "C/m, determine the molar mass of the unknown substance. _g/mol Molar mass unknown substance = 40.0g CCl4 molccly = 2.53 molicly! 153,81 g CCl4 ATb=ikbm kb = 502 Un 0250 g unt solute...

  • The molar mass of a nonelectrolyte is 58.0 g/mol

    The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution containing 16.9 g of this compound and 600.0 g of water. The barometric pressure during the experiment was such that the boiling point of pure water was 99.725 °C.  

  • Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g...

    Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g mL-1, a freezing point of 5.45°C, and a boiling point of 80.2°C. Its freezing point depression and boiling point elevation constants are: Kf = 5.07°C m-1; Kb = 2.53oC m-1. A solution was made by taking 33.88 g of an unknown nonelectrolyte and dissolving it in 175.0 g of benzene. The measured freezing point of the solution was 1.65oC. Calculate the molar mass of...

  • 5. What mass of bacta (FW: 192.095 g/mol), a nonelectrolyte, must be dissolved in 5000.0 g...

    5. What mass of bacta (FW: 192.095 g/mol), a nonelectrolyte, must be dissolved in 5000.0 g of ambori to give a solution with a freezing point of -1.50°C? What is that solution's boiling point? The normal boiling point of ambori is 84°C. The K of ambori is 39.7°C/m and the Ko of ambori is 2.34°C/m. (10 points)

  • A 83.5 g sample of a nonelectrolyte is dissolved in 250.1 g of water. The solution...

    A 83.5 g sample of a nonelectrolyte is dissolved in 250.1 g of water. The solution is determined to have a boiling point of 102.3 °C. What is the molar mass of the compound? (Kb for water is 0.510 °C/m).

  • The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution...

    The molar mass of a nonelectrolyte is 58.0 g/mol. Compute the boiling point of a solution containing 22.7 g of this compound and 600.0 g of water. The barometric pressure during the experiment was such that the boiling point of pure water was 99.725 °C.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT