Question

Consider the following snippet of code :

  ArrayList <String> temp = new ArrayList<String>();
  temp.add(“a”);
  temp.add(”b”);
  temp.add(“c”);
  temp.remove(“z”);
  temp.add(2, “d”);
  temp.set(0, “e”);
  temp.remove(1);
  System.out.println(temp.size() + ” “+ temp.get(1));

What will print on the screen?

	3 b
	3 d
	4 a
	4 e
	Runtime Error

Answer 1

Answer 3 d:

1st we are adding a b c

next removing z which is not present so no impact to the list

after add(2,"d") -> a b d c

set(0,"e") : -> e b d c

remove (1) : a d c

so size is 3 and at index 1 we have 3

Note : Please comment below if you have concerns. I am here to help you

If you like my answer please rate and help me it is very Imp for me