A solid uniform 3.25-kg cylinder, 75.0 cm in diameter and 12.4 cm long, is connected to...
A solid uniform 3.25-kg cylinder, 75.0 cm in diameter and 12.4 cm long, is connected to a 1.50-kg weight over two massless frictionless pulleys as shown in the figure below (Figure 1). The cylinder is free to rotate about an axle through its center perpendicular to its circular faces, and the system is released from rest.
a-How far must the 1.50-kg weight fall before it reaches a speed of 3.30 m/s?
b-How fast is the cylinder turning at this instant?
Homework Answers
A)
Using law of conservation of energy,
(0.5 m + 0.25 M) v^2 = mgh
Height, h = [0.5 x 1.5 + 0.25 x 3.25] x 3.3^2/(1.5 x 9.8) = 1.16 m
B)
Angular velocity, w = v/r = 3.3/0.375 = 8.8 rad/sec
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