What is the angle to the third-order dark fringe (m = 3) for a single slit...

Question

Question

What is the angle to the third-order dark fringe (m = 3) for a single slit of width 37×10−5m if the wavelength of light is 582 nm?

Answer 1

Answer #1

For dark fringe , d Sin(theta) = m(lemda)

=) Sin(theta) = 3×582 × 10^-9 / 37×10^-5 = 47.189×10^-4

=) Theta = Sin^-1(0.0047189) = 0.27 degree

Hence angle theta = 0.27 °

Answer 2

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