Question

The hydrolysis of sucrose (C12H22O11) into glucose and fructose in acidic water has a rate constant of 1.8×10−4s−1 at 25 ∘C.

Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.60 L of a 0.120 M sucrose solution is allowed to react for 195 min.

Answer 1

We know that,

Molar mass of Sucrose = 342.30g/mol.

number of moles Z = (concentration Z)(volume of solution) ...(1)

mass of Z = (number of moles Z)×(molar mass of Z) .....(2)

X = 0.1054M = 0.1054mol/L

.

Change in Number of mole of sucrose = X(Volume of reaction)

Change in Number of mole of Sucrose = (0.1054mol/L)(2.60L)

Change in Number of mole of Sucrose = 0.274mol.

mass of Sucrose that is hydrolyzed will be given as follows.

mass

=(change in Number of moles of sucrose)(molar mass of success)

.

Mass of Sucrose that is hydrolyzed = (0.274mol)(342.30g/mol)

Mass of Sucrose that is hydrolyzed = 93.794g

Answer = 93.794g