A 10 cm, 90° elbow in a horizontal pipe directs flow of water upward at a...
A 10 cm, 90° elbow in a horizontal pipe directs flow of water upward at a rate of 40 kg/s. The elevation difference between centers of the pipe exit and the inlet to the elbow is 50 cm. The weight of the elbow and water can be neglected. The momentum flux correction factor is 1.03 at both elbow inlet and outlet.
Find:
a. gauge pressure at the inlet to the elbow in kPa
b. magnitude of anchoring force need to hold the elbow in place, in N
c. direction of anchoring force in degrees from the positive horizontal axis
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A 10 cm, 90° elbow in a horizontal pipe directs flow of water
upward at a...
Question 3 (12 marks) A reducing elbow is used to deflect water flow at a rate...
Question 3 (12 marks) A reducing elbow is used to deflect water flow at a rate of 25 kg/s in a horizontal pipe upward by an angle 0=60° from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The diameter of the elbow at the inlet isl9 cm and at the exit 2 cm. The elevation difference between the centers of the exit and the inlet is 36 cm. The mass of the elbow and the...
4. A reducing elbow is used to deflect water flow at a rate of 30 lbm/s...
4. A reducing elbow is used to deflect water flow at a rate of 30 lbm/s in a horizontal pipe upward by an angle 30° from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The diameter of the elbow is 4 inch at the inlet and 2 inch at the exit. The elevation difference between the centers of the exit and inlet is 40 inch. The mass of the elbow and the water in it...
please help ...note:do not use momentum flux correction factor..please assume the height A converging elbow turns...
please help ...note:do not use momentum flux correction
factor..please assume the height
A converging elbow turns water through an angle of 60° in a horizontal plane. The flow cross-sectional diameter is d1-200mm at the elbow inlet, and d2-100mm at the outlet. The elbow flow passage volume is 0.02m3 between sections (1) and (2). The water volumetric flow rate is 40 Liters/s and the pressure measured at the inlet is 150 kPa. Neglecting the weight of the elbow, calculate: a- The...
4. An old, rough-surfaced, 2-m-diameter concrete pipe with a Manning coefficient of 0.025 carries water at...
4. An old, rough-surfaced, 2-m-diameter concrete pipe with a Manning coefficient of 0.025 carries water at a rate of 5.0 m'/s when it is half ful. This pipe is to be replaced by a new smooth pipe with a Manning coefficient of 0.012. Determine the diameter of the new pipe if it also is to flow half full with a flow rate of 5.0 m'/s Water initially flowing in the horizontal section of pipe of diameter 12.00 cm shown in...
also need direction of resultant force FIGURE P6-37 6-38 Water flowing in a horizontal 25-cm-diameter pipe...
also need direction of resultant force
FIGURE P6-37 6-38 Water flowing in a horizontal 25-cm-diameter pipe at 8 m/s and 300 kPa gage enters a 90 bend reducing section, which connects to a 15-cm-diameter vertical pipe. The inlet of the bend is 50 cm above the exit. Neglecting any frictional and gravitational effects, determine the net resultant force exerted on the reducer by the water. Take the momentum- flux correction factor to be 1.04. 6 30 A horizontal 4-cm-diameter water...
Water flows steadily through a curved duct that turns the flow through angle = 135 degrees,...
Water flows steadily through a curved duct that turns the flow
through angle = 135 degrees, as shown in Fig. 3. The
cross-sectional area of the duct changes from A1 = 0.025 m2 at the
inlet to A2 = 0.05 m2 at the outlet. The average velocity at the
duct inlet is V1 = 6 m/s. The momentum flux correction factor may
be taken as 1 = 1.01 at the duct inlet and 2 = 1.03 at the its
outlet....
Water flows steadily through a curved duct that turns the flow through angle @= 135º, as...
Water flows steadily through a curved duct that turns the flow through angle @= 135º, as shown in Fig. 3. The cross-sectional area of the duct changes from A1 = 0.025 m² at the inlet to A2 = 0.05 m’ at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as B1 = 1.01 at the duct inlet and B2 = 1.03 at the its outlet. The...
asap please, will rate! 3. Water flows steadily through a curved duct that turns the flow...
asap please, will rate!
3. Water flows steadily through a curved duct that turns the flow through angle 0= 135º, as shown in Fig. 3. The cross-sectional area of the duct changes from Aj 0.025 m² at the inlet to A2 = 0.05 m² at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as Bi= 1.01 at the duct inlet and B2 = 1.03 at the...
please help...add sketch Water flows steadily through a curved duct that turns the flow through angle...
please help...add sketch
Water flows steadily through a curved duct that turns the flow through angle = 1359, as shown in Fig. 3. The cross-sectional area of the duct changes from A1 = 0.025 m’ at the inlet to Az = 0.05 m² at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as B - 1.01 at the duct inlet and B = 1.03 at the...
Show all work and answer all parts of the problem please. The 45 degree elbow nozzle discharges water into the atmosphere. The cross-sectional area of the elbow is 25 cm2 150 cm2 at the inlet and...
Show all work and answer all parts of the problem
please.
The 45 degree elbow nozzle discharges water into the atmosphere. The cross-sectional area of the elbow is 25 cm2 150 cm2 at the inlet and 25 cm2 at the exit. Velocity at point 1 and 2 are given as 2 m/s and 12 m/s 450 respectively. The gage pressure at 1 is 73 kPa 150 em2 30 cm The elevation difference between the centers of the exit and the...
Question 3 (12 marks) A reducing elbow is used to deflect water flow at a rate of 25 kg/s in a horizontal pipe upward by an angle 0=60° from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The diameter of the elbow at the inlet isl9 cm and at the exit 2 cm. The elevation difference between the centers of the exit and the inlet is 36 cm. The mass of the elbow and the...
4. A reducing elbow is used to deflect water flow at a rate of 30 lbm/s in a horizontal pipe upward by an angle 30° from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The diameter of the elbow is 4 inch at the inlet and 2 inch at the exit. The elevation difference between the centers of the exit and inlet is 40 inch. The mass of the elbow and the water in it...
please help ...note:do not use momentum flux correction
factor..please assume the height
A converging elbow turns water through an angle of 60° in a horizontal plane. The flow cross-sectional diameter is d1-200mm at the elbow inlet, and d2-100mm at the outlet. The elbow flow passage volume is 0.02m3 between sections (1) and (2). The water volumetric flow rate is 40 Liters/s and the pressure measured at the inlet is 150 kPa. Neglecting the weight of the elbow, calculate: a- The...
4. An old, rough-surfaced, 2-m-diameter concrete pipe with a Manning coefficient of 0.025 carries water at a rate of 5.0 m'/s when it is half ful. This pipe is to be replaced by a new smooth pipe with a Manning coefficient of 0.012. Determine the diameter of the new pipe if it also is to flow half full with a flow rate of 5.0 m'/s Water initially flowing in the horizontal section of pipe of diameter 12.00 cm shown in...
also need direction of resultant force
FIGURE P6-37 6-38 Water flowing in a horizontal 25-cm-diameter pipe at 8 m/s and 300 kPa gage enters a 90 bend reducing section, which connects to a 15-cm-diameter vertical pipe. The inlet of the bend is 50 cm above the exit. Neglecting any frictional and gravitational effects, determine the net resultant force exerted on the reducer by the water. Take the momentum- flux correction factor to be 1.04. 6 30 A horizontal 4-cm-diameter water...
Water flows steadily through a curved duct that turns the flow
through angle = 135 degrees, as shown in Fig. 3. The
cross-sectional area of the duct changes from A1 = 0.025 m2 at the
inlet to A2 = 0.05 m2 at the outlet. The average velocity at the
duct inlet is V1 = 6 m/s. The momentum flux correction factor may
be taken as 1 = 1.01 at the duct inlet and 2 = 1.03 at the its
outlet....
Water flows steadily through a curved duct that turns the flow through angle @= 135º, as shown in Fig. 3. The cross-sectional area of the duct changes from A1 = 0.025 m² at the inlet to A2 = 0.05 m’ at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as B1 = 1.01 at the duct inlet and B2 = 1.03 at the its outlet. The...
asap please, will rate!
3. Water flows steadily through a curved duct that turns the flow through angle 0= 135º, as shown in Fig. 3. The cross-sectional area of the duct changes from Aj 0.025 m² at the inlet to A2 = 0.05 m² at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as Bi= 1.01 at the duct inlet and B2 = 1.03 at the...
please help...add sketch
Water flows steadily through a curved duct that turns the flow through angle = 1359, as shown in Fig. 3. The cross-sectional area of the duct changes from A1 = 0.025 m’ at the inlet to Az = 0.05 m² at the outlet. The average velocity at the duct inlet is V1 = 6 m/s. The momentum flux correction factor may be taken as B - 1.01 at the duct inlet and B = 1.03 at the...
Show all work and answer all parts of the problem
please.
The 45 degree elbow nozzle discharges water into the atmosphere. The cross-sectional area of the elbow is 25 cm2 150 cm2 at the inlet and 25 cm2 at the exit. Velocity at point 1 and 2 are given as 2 m/s and 12 m/s 450 respectively. The gage pressure at 1 is 73 kPa 150 em2 30 cm The elevation difference between the centers of the exit and the...
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