50.0 g of calcium carbonate are placed in a container with 20.0 g of CaO and 1.04 atm carbon dioxide. What will the equilibrium pressure be in the container? How much calcium carbonate will be left at equilibrium?
CaCO3 (s) ⇌ CaO(s) + CO2 (g) KP = 1.04 atm at 900 °C
50.0 g of calcium carbonate are placed in a container with 20.0 g of CaO and...
CaCO3(s) = Cao (s)+CO2 (g) When heated strongly, solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas, as represented by the equation above. A 2.0 mol sample of CaCO3(s) is placed in a rigid 100. L reaction vessel from which all the air has been evacuated. The vessel is heated to 898°C at which time the pressure of CO2(g) in the vessel is constant at 1.00 atm, while some CaCO3(s) remains in the vessel. a. Calculate...
Calcium oxide and carbon dioxide react to form calcium carbonate, like this: CaO(s)+CO,(g)→ CaCO3(s) At a certain temperature, a chemist finds that a 2.5 L reaction vessel containing a mixture of calcium oxide, carbon dioxide, and calcium carbonate at equilibrium has the following composition: compound amount CaO | 20.5 g CO2 17.1 g CaCo3 66.7 g Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K = 0 xs ?
QUESTION 3 Solid calcium carbonate (CaCO3) decomposes into solid calcium oxide (Cao) and carbon dioxide (CO) gas according to the following heterogeneous equilibrium: CaCO3(s) = Cao(s) + CO2(g) What is the correct equilibrium constant expression for this equation? OK (CaCO3] [Cao][CO2] ok, = [Coz] [Cao][CO.” [CaCO3] okea 0K = [Cao][CO2] [Ca][CO] (CaCO3] ok
Calcium oxide (lime) reacts with carbon dioxide to form calcium carbonate (chalk). CaO(s) + CO2(g) → CaCO3(s) ∆H = –178.4 kJ How many kilojoules of heat are evolved in the reaction of 0.500 kg CaO(s) (molar mass 56.08 g/mol) with an excess of carbon dioxide?
At 1073 K, the equilibrium pressure of carbon dioxide above mixtures of calcium carbonate and calcium oxide is 183 torr. (a) If 5.0 g of solid calcium carbonate is placed in a 4000- mL container at 1073 K, give the final amounts of the various species. CaCO3 = Caos DOO CO2 = (b) The same as (a), except 0.50 g of CaCO3 is placed in the container. CaCO3 = DO Ca0 = CO2 =
Gasses a) What is the molar mass of a gas if 5.50 g of the gas fills a 50.0 L container with a pressure of 1590 torr at 30°C? b) 100.0 g of calcium carbonate (CaCO3 ) in a 25.0 L container is heated to 600°C, producing calcium oxide (CaO) and carbon dioxide (CO2). What is the pressure generated in the container when all of the CaCO3 is consumed? after it is allowed to cool down to 20°C? CaCO3 (s)...
CaCO3(s) + heat --> CO2(g) + CaO(s) How many grams of calcium carbonate will be needed to form 4.29 liters of carbon dioxide?
At high temperatures calcium carbonate decomposes into calcium oxide and carbon dioxide. CaCO3 (solid) {> Cao (solid) + CO2 (gas) Find the equilibrium pressure of this system at 1200 K if the equilibrium constant at 1400 K is 26. If the AGº of CaO(solid) and CaCO3 (solid) at 298 Kare -604 and -1128.8 kJ/mol respectively, estimate the equilibrium constant Kat 298 K and the equilibrium pressure. Discuss the effect of pressure on both the conversion of CaCO3 and the final...
When solid calcium carbonate is heated, it decomposes according to the reaction: CaCO3(s) ⇄ CaO(s) + CO2(g) Kp = 0.50 A sample of CaCO3 is placed in a 1.0 L evacuated flask and heated to 830 Celsius. What is the mass of CaO produced when equilibrium is established? Please show all work. a) 0.411 g b) 0.500 g c) 0.00552 g d) 5.3 g e) 0.310 g
CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K. When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.300 atm of CO2 is added, while keeping the temperature constant and the system is allowed to reach again equilibrium. What will be the final mass of CaCO3? 7.47 g 12.54 g 18.01 g 2.00 g 10.01 g