Question

Write program in C++:

Function name: Average1D: The Function takes an integer array of 1 Dimension of any size that is given from the main program. The function returns the average of the numbers that less than or equal to 50.

Answer 1

#include <iostream>

using namespace std;

double Average1D(int arr[], int size) {
    double total = 0, count = 0;
    for (int i = 0; i < size; ++i) {
        if (arr[i] <= 50) {
            total += arr[i];
            size++;
        }
    }
    return total / count;
}

int main() {
    int numbers[] = {4, 9, 19, 99, 93, 52, 20};
    int size = sizeof(numbers)/sizeof(int);
    cout << "Average = " << Average1D(numbers, size) << endl;
    return 0;
}