Question

For each of the following solutions, identify the solute as an electrolyte or non-electrolyte. For electrolyte solutions, identify the concentration of cations and anions in the solution. For each solution, identify the total concentration of dissolved particles.

Solution	Electrolyte / non-Electrolyte	Cation	Anion	Total Dissolved Particles
0.1 M KCl
0.2 M CH3OH
0.3 M Ca(NO3)2
0.3 M Na3PO4
0.2 M NaOH

It's for presentation, so explain why pls.

Answer 1

KCl

It is an ionic compound. It dissociates into cation K⁺ and Cl^-. It is an Electrolyte.

Total dissolved particle is 2.

KCl ----> K⁺ + Cl^-

Total concentration of dissoloved Conc = [K⁺] + [Cl^-]

= 0.1 + 0.1

=0.2

CH₃OH

It is an covalent compound. It does not dissociate into ions in aqueous solution. So it non electrolyte.

Total Con of dissolved particle = [CH₃OH]

= 0.2 M

Ca(NO3)2

It is an ionic compound. It dissociates into cation Ca⁺² and NO^-3. It is an Electrolyte.

Ca(NO3)2 ----> Ca⁺² +  2NO^-3

total dissolved particles= 3

Total Conc of dissolved particles = [ Ca⁺² ]+  2[NO^-3]

= 0.3 + 0.6

= 0.9M

Na₃PO₄

0.3 M Na₃PO₄

It is an ionic compound. It dissociates into cation Na⁺ and PO₄^-3. It is an Electrolyte.

  

Na₃PO₄ ------> 3 Na⁺ + PO₄^-3

total dissolved particles= 4

Total Conc of dissolved particles = 3[ Na⁺ ]+  [PO₄^-3]

=3(0.3) + 0.3

=1.2

NaOH

It is an ionic compound. It dissociates into cation Na⁺ and OH^-. It is an Electrolyte.

Solve Similarly.