Summary statistics for 10 drivers' car insurance premiums quoted by a local agent and an online company are shown in the table to the right. The accompanying table has displays for each company's quotes and for the difference left parenthesis Local minus Online right parenthesis . Variable Count Mean StdDev Local 10 802.8 220.587 Online 10 754.8 284.838 PriceDiff 10 48.0 155.531 Test an appropriate hypothesis to see if there is evidence that drivers might save money by switching to the online company. LOADING... Click the icon to view the data table, boxplot, and histogram for insurance premiums. Identify the null and alternative hypotheses. A. Upper H 0: mu Subscript dequals0 Upper H Subscript Upper A: mu Subscript dnot equals0 B. Upper H 0: mu Subscript dequals0 Upper H Subscript Upper A: mu Subscript dgreater than0 C. Upper H 0: mu 1 minus mu 2equals0 Upper H Subscript Upper A: mu 1 minus mu 2greater than0 D. Upper H 0: mu 1 minus mu 2equals0 Upper H Subscript Upper A: mu 1 minus mu 2not equals0 Calculate the test statistic. tequals nothing (Round to three decimal places as needed.) Calculate the P-value. P-valueequals nothing (Round to four decimal places as needed.) State the conclusion. Assume alphaequals0.05. ▼ Reject Fail to reject Upper H 0. There ▼ is is not sufficient evidence that online premiums, on average, are lower.
let d = local - online
and
Conclusion: There is not sufficient evidence that online premiums, on average, are lower.
Summary statistics for 10 drivers' car insurance premiums quoted by a local agent and an online...
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.10 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). Household Paper Plastic 1 6.16 5.88 2 16.39 9.70 3 6.33 3.86 4 11.36 10.25 5 12.43 8.57 6 7.98 6.09 7 11.42 12.81...
Data were collected on the annual mortality rate (deaths per 100,000) for males in 61 large towns in England and Wales. The data set also notes for each town whether it was south or north of Derby. The summary statistics are given below. Is there a significant difference in mortality rates in the two regions? Answer parts a and b. Assume a significance level of alphaequals0.05. Group Count Mean Median StdDev North 28 1612.31 1612 125.97 South 33 1592.56 1575...
The following table shows the hot dogs bought from a street vendor over the course of eight days ("Demand"). Also shown is the temperature for each day in degrees Celsius. nbsp Temperature (C*): 22 12 22 19 7 11 16 23 Demand: 50 30 36 40 18 25 40 31 A linear regression on the data gives the equation below. Complete parts a through d below. Predicted Demand equals 13.22 plus 1.24 left parenthesis Temperature right parenthesis a. Calculate the...
The table to the right contains observed values and expected values in parentheses for two categorical variables, X and Y, where variable X has three categories and variable Y has two categories. Use the table to complete parts (a) and (b) below. Upper X 1 Upper X 2 Upper X 3 Upper Y 1 34 left parenthesis 35.67 right parenthesis 43 left parenthesis 44.77 right parenthesis 51 left parenthesis 47.56 right parenthesis Upper Y 2 17 left parenthesis 15.33 right...
An insurance agent randomly selected 10 of his clients and checked online price quotes for their policies. His summaries of the data are shown, where Diff is Local minus−Online. Variable Count Mean StdDev Local 10 970.600 400.921 Online 10 928.800 308.986 Diff 10 41.8000 170.607 Test an appropriate hypothesis to see if there is evidence that drivers might save money by switching to an online agent. Use α= 0.05. HO: μd=0 HA: μd>0 Compute...
As concrete cures, it gains strength. The following data represent the 7-day and 28-day strength in pounds per square inch (psi) of a certain type of concrete. Complete parts (a) through (f) below. 7-Day Strength (psi), x 3340 3380 3330 2300 2480 28-Day Strength (psi), y 4630 5020 4850 4070 4120 (a) Treating the 7-day strength as the explanatory variable, x, use technology to determine the estimates of beta 0 and beta 1. beta 0almost equalsb 0equals nothing (Round to...
As concrete cures, it gains strength. The following data represent the 7-day and 28-day strength in pounds per square inch (psi) of a certain type of concrete. Complete parts (a) through (f) below. 7-Day Strength (psi), x 3340 3380 3330 2300 2480 28-Day Strength (psi), y 4630 5020 4850 4070 4120 (a) Treating the 7-day strength as the explanatory variable, x, use technology to determine the estimates of beta 0 and beta 1. beta 0almost equalsb 0equals nothing (Round to...
An agency examined the relationship between the ozone level (in parts per million or ppm) and the population (in millions) of cities. Part of the regression analysis is shown to the right. Complete parts a and b below. Dependent variable is: Ozone R squaredequals82.2% s=5.158 with 16-2=14 df Variable Coeff SE (Coeff) Intercept 18.769 2.311 Population 6.701 2.027 a) It is suspected that the greater the population of a city, the higher its ozone level. Is the relationship statistically...
A data set includes data from student evaluations of courses. The summary statistics are nequals 91, x overbar equals4.17, sequals 0.69. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25 . Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A....
Several students were tested for reaction times (in thousandths of a second) using their right and left hands. (Each value is the elapsed time between the release of a strip of paper and the instant that it is caught by the subject.) Results from five of the students are included in the graph to the right. Use a 0.10 significance level to test the claim that there is no difference between the reaction times of the right and left hands....