18.- If three people, randomly selected, are arrested on the street, what are the chances that...
18.- If three people, randomly selected, are arrested on the
street, what are the chances that
a) all of them were born on Friday; A= 0.0029
b) two of them were born on Friday; A=0.0525
c) None of them was born on Monday? A= 0.6297
Homework Answers
There are 7 days in a week.
So, P(Friday) = 1 / 7
a)
P(All three born on Friday) = 1/7 * 1/7 * 1/7
= 0.0029
b)
P(Friday) = 1/7 , P(Not Friday) = 1 - 1/7 = 6/7
P(Two of them born on Friday) = 3C2 * (1/7 * 1/7 *6/7)
= 3 * 0.01749
= 0.0525
c)
P(Monday) = 1 / 7 , P(Not Monday) = 1 - 1/7 = 6/7
P(None of them born on Monday) = 6/7 * 6/7 * 6/7
= 0.6297
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