Scores in the first and fourth (final) rounds for a sample of 20 golfers who competed in golf tournaments are shown in the following table.
Player | First Round |
Final Round |
---|---|---|
Golfer 1 | 70 | 72 |
Golfer 2 | 71 | 72 |
Golfer 3 | 70 | 74 |
Golfer 4 | 72 | 71 |
Golfer 5 | 70 | 69 |
Golfer 6 | 67 | 67 |
Golfer 7 | 71 | 68 |
Golfer 8 | 68 | 73 |
Golfer 9 | 67 | 73 |
Golfer 10 | 70 | 69 |
Player | First Round |
Final Round |
---|---|---|
Golfer 11 | 72 | 72 |
Golfer 12 | 72 | 70 |
Golfer 13 | 70 | 73 |
Golfer 14 | 70 | 75 |
Golfer 15 | 68 | 70 |
Golfer 16 | 68 | 66 |
Golfer 17 | 71 | 70 |
Golfer 18 | 70 | 68 |
Golfer 19 | 69 | 68 |
Golfer 20 | 67 | 71 |
Suppose you would like to determine if the mean score for the first round of a golf tournament event is significantly different than the mean score for the fourth and final round. Does the pressure of playing in the final round cause scores to go up? Or does the increased player concentration cause scores to come down?
Use
α = 0.10
to test for a statistically significantly difference between the population means for first- and fourth-round scores.
State the null and alternative hypotheses. (Use μd = mean score first round − mean score fourth round.)
H0:
μd > 0
Ha:
μd ≤ 0
H0:
μd = 0
Ha:
μd ≤ 0
H0:
μd ≠ 0
Ha:
μd = 0
H0:
μd = 0
Ha:
μd ≠ 0
H0:
μd ≤ 0
Ha:
μd > 0
Calculate the value of the test statistic. (Round your answer to three decimal places.)
Calculate the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Reject H0. There is insufficient evidence to conclude that the mean score for the first round of a golf tournament is significantly different than the mean score for the fourth and final round.Reject H0. There is sufficient evidence to conclude that the mean score for the first round of a golf tournament is significantly different than the mean score for the fourth and final round. Do not Reject H0. There is sufficient evidence to conclude that the mean score for the first round of a golf tournament is significantly different than the mean score for the fourth and final round.Do not reject H0. There is insufficient evidence to conclude that the mean score for the first round of a golf tournament is significantly different than the mean score for the fourth and final round.
(b)
What is the point estimate of the difference between the two population means? (Use mean score first round − mean score fourth round.)
For which round is the population mean score lower?
The mean of the fourth round scores was lower than the mean of the first round scores.The mean of the first round scores was lower than the mean of the fourth round scores.
(c)
What is the margin of error for a 90% confidence interval estimate for the difference between the population means? (Round your answer to two decimal places.)
Could this confidence interval have been used to test the hypothesis in part (a)? Explain.
Yes. One could check to see if the 90% confidence interval includes a difference of zero. If the interval does not contain 0, the difference is not statistically significant.
Yes. One could check to see if the 90% confidence interval includes a difference of 1. If the interval does not contain 1, the difference is not statistically significant.
Yes. One could check to see if the 90% confidence interval includes a difference of zero. If the interval contains 0, the difference is not statistically significant.
Yes. One could check to see if the 90% confidence interval includes a difference of 1. If the interval contains 1, the difference is not statistically significant.
No. One can not use a confidence interval to test hypothesis in part (a) because hypothesis tests and confidence intervals are two different things.
Excel output:
Player | First Round | Final Round | t-Test: Paired Two Sample for Means | ||||
Golfer 1 | 70 | 72 | |||||
Golfer 2 | 71 | 72 | First Round | Final Round | |||
Golfer 3 | 70 | 74 | Mean | 69.65 | 70.55 | ||
Golfer 4 | 72 | 71 | Variance | 2.765789474 | 6.05 | ||
Golfer 5 | 70 | 69 | Observations | 20 | 20 | ||
Golfer 6 | 67 | 67 | Pearson Correlation | 0.139601116 | |||
Golfer 7 | 71 | 68 | Hypothesized Mean Difference | 0 | |||
Golfer 8 | 68 | 73 | df | 19 | |||
Golfer 9 | 67 | 73 | t Stat | -1.452966315 | |||
Golfer 10 | 70 | 69 | P(T<=t) one-tail | 0.081275 | |||
Golfer 11 | 72 | 72 | t Critical one-tail | 1.729132812 | |||
Golfer 12 | 72 | 70 | P(T<=t) two-tail | 0.162549999 | |||
Golfer 13 | 70 | 73 | t Critical two-tail | 2.093024054 | |||
Golfer 14 | 70 | 75 | |||||
Golfer 15 | 68 | 70 | |||||
Golfer 16 | 68 | 66 | |||||
Golfer 17 | 71 | 70 | |||||
Golfer 18 | 70 | 68 | |||||
Golfer 19 | 69 | 68 | |||||
Golfer 20 | 67 | 71 |
Answer:
Part a.
Value of the test statistic= -1.453
p-value=0.1625
Since p-value>0.10, so
Do not reject H0. There is insufficient evidence to conclude that the mean score for the first round of a golf tournament is significantly different than the mean score for the fourth and final round.
Part b. The point estimate of the difference between the two population means=69.65-70.55=-0.9
Part c.
90% CI for (-0.9-1.07, -0.9+1.07)=(-1.97, 0.17).
Yes. One could check to see if the 90% confidence interval includes a difference of zero. If the interval contains 0, the difference is not statistically significant.
Scores in the first and fourth (final) rounds for a sample of 20 golfers who competed...
You may need to use the appropriate technology to answer this question. Scores in the first and fourth (final) rounds for a sample of 20 golfers who competed in golf tournaments are shown in the following table. Player First Round Final Round Golfer 1 70 72 Golfer 2 71 72 Golfer 3 70 73 Golfer 4 72 71 Golfer 5 70 69 Golfer 6 67 67 Golfer 7 71 68 Golfer 8 68 73 Golfer 9 67 73 Golfer 10...
Scores in the first and fourth (final) rounds for a sample of 20 golfers who competed in golf tournaments are shown in the following table First Final Round Round First Final Round Round Player Golfer 1 Golfer 2 Golfer 3 Golfer 4 Golfer 5 Golfer 6 Golfer 7 Golfer 8 Golfer 9 Golfer 1070 Playe Golfer 11 Golfer 12 72 Golfer 13 70 Golfer 14 Golfer 15 68 Golfer 16 68 Golfer 17 71 Golfer 18 Golfer 19 69 Golfer...
Scores in the first and fourth (final) rounds for sample of 20 golfers who competed in golf tournaments are shown in the following table. First Final Player Round Golfer 1 Golfer 2 Golfer 3 Golfer 4 Golfer 5 Golfer 6 Golfer 7 Golfer 8 Golfer 9 Golfer 10 Round Player Round Round 70 72 Golfer 11 Golfer 12 Golfer 13 Golfer 14 Golfer 15 Golfer 166 Golfer 17 71 Golfer 18 Golfer 19 Golfer 20 67 72 72 72 70...
9.72 G olf Scores In a professional golf tournament (c) Find a 95% interval to predict the average final e players participate in four rounds of golf and the player with the lowest score after all four rounds is th score of all golfers who shoot a +3 in the first round at the Masters. e champion. How well does a player's performance in the first round of the tournament predict the final score? Table 9.6 shows the first round...
So far this year, a professional golfer has recorded the following scores in his 36 golf games: Stem-and-leaf of golf scores n = 36 Leaf Unit = 0.10 65|00 66|00 67|000000 68|000000 69|000000 70|0 71|000 72|00 73|00000 74|00 75|0 The first quartile for his golf scores is ____________strokes. Please type the correct answer in the following input field, and then select the submit answer button or press the enter key when finished.
A standardized exam consists of three parts: math, writing, and critical reading. Sample data showing the math and writing scores for a sample of 12 students who took the exam follow. Student Math Writing 1 540 474 2 432 380 3 528 463 4 574 612 5 448 420 6 502 526 7 480 430 8 499 459 9 610 615 10 572 541 11 390 335 12 593 613 (a) Use a 0.05 level of significance and test for...
Question 15 0/10 pts At a recent PGA tournament (the Honda Classic at Palm Beach Gardens, Florida) the following scores were posted for eight randomly selected golfers for two consecutive days, Thursday (X1) and Friday (X2). Golfer Thursday Friday 1 2 3 4 5 6 7 8 6765 68 68 68 70 69 70 | 68 70 69 71 72 69 70 70 Source: Washington Observer-Reporter. At a 0.05 level of significance, is there evidence of a difference in mean...
The following table contains information on matched sample values whose differences are normally distributed. Use Table 2. Number Sample 1 Sample 2 1 16 20 2 12 13 3 20 22 4 20 22 5 17 20 6 14 16 7 16 18 8 18 21 a. Construct the 99% confidence interval for the mean difference μD. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at...
Just need C), D), E). (I got a t value od 1.8856) Sportscasters are interested in whether professional golfers play better in their first round. Consider the following data. Let B=score in the final round of a professional golf tournament and A=score in the first round of a professional golf tournament. A random sample of 5 finalists in the British Open had the following data: Player B (last round) A (first round) 1 73 66 2 68 70 3 73...
The average final exam score for the statistics course is 76%. A professor wants to see if the average final exam score for students who are given colored pens on the first day of class is different. The final exam scores for the 13 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 74, 88, 68,95, 84, 83, 70, 97, 66, 82, 67, 67, 86 What can be...