A simple random sample of 31 observations was taken from a large population. The sample mean equals 5. Five is a
population parameter. |
standard error. |
point estimate. |
population mean. |
A simple random sample of 31 observations was taken from a large population. The sample mean...
A simple random sample of 81 observations was taken from a large population. The sample mean and the sample standard deviation were determined to be 165 and 225 respectively. The standard error of the mean is
A simple random sample of 64 observations was taken from a large population. The sample mean and the standard deviation were determined to be 70 and 12 respectively. The standard error of the mean is . . . (hint: enter the answer with one decimal place)
QUESTION 16 5 points A simple random sample of 64 observations was taken from a large population. The sample mean and the standard deviation were determined to be 320 and 120 respectively. The standard error of the mean is .1.875 .15 0.5 0.40
A simple random sample of size 64 is taken from a population of size 800. The sample mean is determined to be 2,550 with a standard deviation of 500. An estimate of the standard error of the mean (for the total) is: Correct answer = 47,958.32. Please show me the calculation.
Suppose that a simple random sample is taken from a normal population having a standard deviation of 15 for the purpose of obtaining a 95% confidence interval for the mean of the population. a. If the sample size is 44, obtain the margin of error. b. Repeat part (a) for a sample size of 25
Suppose a simple random sample of 300 was taken from a large population. The sample had 90% successes. For a 95% confidence level, find the following, rounded to the 4th decimal place. Use your T-Table to find the margin of error. a) How many successes were there? b) - c) d) Margin of Error = Points possible: 4 This is attempt 1 of 3. Message instructor about this question Submit
Suppose that a simple random sample is taken from a normal population having a standard deviation of 6 for the purpose of obtaining a 90% confidence interval for the mean of the population. The margin of error for a sample size of 16 is ??? (Round to four decimal places as needed.) The margin of error for a sample size of 81 is ??? (Round to four decimal places as needed.)
Question 10 A sample of 51 observations will be taken from a process (an infinite population). The population proportion equals 0.85. The probability that the sample proportion will be between 0.9115 and 0.946 is 0.8633 0.6900 0.0819 0.0345 question 16. From a population of 200 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is determined that the sample mean is 56. The standard error of the mean is 3 2 greater...
Suppose that a simple random sample is taken from a normal population having a standard deviation of 11 for the purpose of obtaining a 95% confidence interval for the mean of the population. a. If the sample size is 16, obtain the margin of error. b. Repeat part (a) for a sample size of 81. a. The margin of error for a sample size of 16 is ??? (Round to two decimal places as needed.) b. The margin of error...
A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55. Determine the 99% confidence interval for the population mean. (Round your answers to 2 decimal places.) Confidence interval for the population mean is _______ and _______ .A research firm conducted a survey to determine the mean amount Americans spend on coffee during a week. They found the distribution of weekly spending followed the normal distribution with a population standard deviation...