---------------- TO BE COMPLETED USING RSTUDIO------------------
Use the approximate value for the degrees of freedom
(the smallest between ?1 − 1 and ?2 − 1).
Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and population 2 does not. The data from these two samples (in beats per minute) are given below:
Exercise group (sample from population 1): 65.6, 67.5, 59.9, 70.6, 62.4, 64.9, 63.3, 66.3, 62, 69.5
No exercise group (sample from population 2): 74.2, 70.8, 78.2, 76.8, 78.5, 76.1, 74.7, 76.3, 74.2, 77.7, 74.3, 82.5
Estimate the difference in mean resting heart rates between the two groups using a 9696% confidence interval.
Using a complete test of hypothesis at an ?=0.04 level of significance, is there evidence to conclude that those who exercise regularly have lower resting heart rates?
(a) Test the claim that those who exercise regularly have lower resting heart rates than those who do not. Use the level of significance given to you in WW. You must include: i) null and alternative hypotheses; ii) test statistic; iii) P-value; iv) decision in term of the null hypothesis; v) decision in context.
(b) Create a properly labelled plot that includes the sampling distribution of the statistic under the null hypothesis, the value of the statistic as a vertical line, and the P-value.
---------------- TO BE COMPLETED USING RSTUDIO------------------ Use the approximate value for the degrees of freedom (the...
Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and Population 2 does not. The data from these two samples is given below: Population 1: 72, 73, 63, 68, 65, 67, 67 Population 2: 69, 70, 74, 68, 68, 76, 73, 74 Is there evidence, at an ?=0.05 α = 0.05 level of significance, to conclude that those who exercise regularly have lower resting heart rates? Carry out an appropriate hypothesis test, filling in...
Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and Population 2 does not. The data from these two samples is given below: Population 1: 71, 66, 71, 68, 67, 68, 68 Population 2: 75, 69, 72, 71, 72, 69, 69, 70 Is there evidence, at an ?=0.08 level of significance, to conclude that there those who exercise regularly have lower resting heart rates? (Assume that the population variances are equal.) Carry out an...
Test the given claim. Use the P-value method or the traditional method as indicated. Identify the null hypothesis, alternative hypothesis, test statistic, critical value(s) or P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. The mean resting pulse rate for men is 72 beats per minute. A simple random sample of men who regularly work out at Mitch's Gym is obtained and their resting pulse rates (in beats per minute) are listed below. Use a...
Test the given claim. Use the P-value method or the traditional method as indicated. Identify the null hypothesis, alternative hypothesis, test statistic, critical value(s) or P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. The mean resting pulse rate for women is 72 beats per minute. A simple random sample of women who regularly work out at the local gym is obtained and their resting pulse rates (in beats per minute) are listed below. Use...
(a) Find 6,-x2). answer: (b) Determine the rejection region for the test of H. : (H1 - H2) = 2.1 and H,:(H1 - H2) > 2.1 Use a = 0.01. Z > (c) Compute the test statistic. z = The final conclustion is A. We can reject the null hypothesis that (H1-H2) = 2.1 and accept that (H1-H2) > 2.1. OB. There is not sufficient evidence to reject the null hypothesis that (M - M2) = 2.1. (d) Construct a...
statistics help
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In a sample of 200 male students, 130 said they exercise regularly. In a sample of 300 female students, 180 said they exercise regularly. Test the claim that male students exercise more regularly than female students, at the alpha = 0.05 significance level. Let the population of men be labeled M and the population of women be labeled W. = proportion of male that exercise = proportion of female students that exercise Hypothesis Test: : = : > Information: Test...
2. [25 POINTS = 15+101 BONNIE (WHO WORKS AS INSURANCE ANALYST) COLLECTED DATA FOR TWO INDEPENDENT GROUPS OF CAR POLICIES, EACH GROUPS INCLUDED n1 = n2 8 MONTHLY PREMIUM VALUES. BONNIE ASSUMED THAT THE POPULATION VARIANCES FOR TWO GROUPS ARE KNOWN AS (σ)-(o2)2 = 9 SAMPLE SUMMARIES WERE FOUND AS FOLLOWS (SAMPLE MEAN FOR GROUP I) = 33.40 AND (SAMPLE VARIANCE) = 7 (SAMPLE MEAN FOR GROUP II)-37.30 AND (SAMPLE VARIANCE)-11 AT THE 1% SIGNIFICANCE LEVEL, DOES BONNIE HAVE SUFFICIENT...
You wish to test the following claim (HaHa) at a significance level of α=0.002α=0.002. Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1<μ2Ha:μ1<μ2 You obtain the following two samples of data. Sample #1 Sample #2 78.5 66.6 90.1 69.7 76.1 82.9 78.7 77.3 84.8 71 76.9 92.5 65.2 71.7 76.5 63.3 66.6 76.9 74.7 85.2 81.1 84.5 91.2 75.5 76.1 73.3 89.3 69.9 57.9 69.1 82.7 71.9 70.2 89.3 79.3 73.9 65.2 73.9 83.2 74.4 80.3 69.5 81.8 78 94.8 67 91.1 89.2 80.2 73.9 85 81.8...