Question

Two cars collide (No external forces) Car 1 has a mass of 2000kg and a velocity of 40 m/s westward. After colliding with the second car (velocity unknown) the 1st car has a velocity of 10 m/s westward.

1st car momentum = 80000 Ns west
1st car velocity change = 30 m/s east.
1st car change in momentum = 60,000 Ns east.
If a 1st passenger (m=50kg) is riding the first car, what impulse does the first car apply on the first passenger? (Ignoring the extra mass). 1500 Ns East (50kg * [10-40])
If a second identical passenger (m=50kg) is riding the 2nd car, what impulse does the second car apply to the second passenger? 1500 Ns West (50kg * [30])

The question are:

Is it possible for the average force applied onto the second passenger resulting from the collision to be less than the average force applied onto the first passenger?

a: yes, if the 1st passenger is wearing a seat belt.
b: yes, if the time that the force acts on the second passenger is sufficiently less than the acting on the first.
c: No, the 1st car is more massive than the 2nd car, so the first passenger will experience a smaller force regardless of other factors.
d: no, both passengers have the same mass so they experience the same stopping force.
e: yes, if the time that the force acts on the second passenger is sufficiently greater than that acting on the first.

If a stopping force is applied from the 1st car onto the first passenger for a time interval of 0.01 seconds, what is the magnitude of this force?

a:1500n b: 300,000n c: 3000n d: 150,000n e: 200,000n

If a stopping force is applied from the 2nd car onto the second passenger for a time interval of 1.00 seconds, what is the magnitude of this force?

a:1500n b: 300,000n c: 3000n d: 150,000n e: 200,000n

Thanks for your help.

Answer 1

Kindly rate (this and the previous answer too) :)