The time to failure of a digital camera (in hours) is distributed exponentially with a parameter 10^-4.
If a camera has lasted 10,000 hours, find the probability that it will last another 10,000 hours or longer.
The time to failure of a digital camera (in hours) is distributed exponentially with a parameter...
1. The time to failure of a digital camera (in hours) is distributed exponentially with parameter 10^−4 . a) Find the expected time to failure. (5) b) Find the probability that the camera will last less than 9,000 hours or more than 12,000 hours. (10) c) Find the probability that the camera will last more than 10,000 hours. (10) d) If the camera has lasted 10,000 hours, find the probability that it will last another 10,000 hours or longer. (10...
Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with parameter λ (lambda) = 0.5.What's the probability that a repair takes less than 5 hours? AND what's the conditional probability that a repair takes at least 11 hours, given that it takes more than 8 hours?
Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with parameter λ=0.8, i.e., mean = 1/lambda. What is (a) the probability that a repair takes less than 77 hours?
4. Each time a machine is repaired, it remains up and working for an exponentially distributed time with rate λ. It then fails, and its failure is either of two types. If it is type 1 failure, then the time to repair the machine is exponentially distributed with mean μ1; if it is a type 1 failure, then the time to repair the machine is exponentially distributed with mean μ2. Each failure is, independently of the time it took the...
The average time between failures of a laser machine is exponentially distributed with a mean of 40,000 hours. a) What is the expected time until 4th failure? b) What is the probability that the time to the 5th failure is greater than 80,000 hours?
The time between failures of a laser in a machine, X, is exponentially distributed with a mean of 25,000 hours. In other words, 1 a= (failures/hour). 25,000 Exponential Distribution (pdf): f(x) = 1.0-\x, for x > 0. (a) What is the probability that the next failure occurs in 27,000 hours? (b) What is the expected time until the third failure? (c) What is the probability that the time until the third failure exceeds 25,000 hours?
The lifetime of a type-A bulb is exponentially distributed with parameter λ. The lifetime of a type-B bulb is exponentially distributed with parameter μ, where μ>λ>0. You have a box full of lightbulbs of the same type, and you would like to know whether they are of type A or B. Assume an a priori probability of 1/4 that the box contains type-B lightbulbs. Assume that λ=3 and μ=4. Find the LMS estimate of T2, the lifetime of another lightbulb...
Suppose d machines are subject to failures and repairs. The failure times are exponentially distributed with parameter μ, and the repair times are exponentially distributed with parameter λ. Let x(t) denote the number of machines that are in satisfactory order at time t. If there is only one repairman, then under appropriate reasonable assumptions, X(t), t 2 0, is a birth and death process on {O, 1,..., d} with birth rates λχ-λ, 0 x < d, and death rates μΧ_xp,...
The time T before a certain bereset is exponentially distributed with the mean of 3 hours. a) whit is the probability that 5 hours pass before the circuit breaker turnsn off for the first time? b) SUppose a random vairable V is given by V = 3y + 1. Find the density function of V