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Susan and Jack are married and plan to have four children. Susan wants to have two...

Susan and Jack are married and plan to have four children. Susan wants to have two girls and two boys; while Jack wants three boys and one girl. Assuming they have four children, what is the probability for each outcome (in any order) and who has better chances of getting what she/he wants.

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Answer #1

Probability of having a boy or girl is 1/2

Probability that outcome is as per Susan's wish,
4C2 * (0.5)^2 * (0.5)^2
= 0.375

Probability that outcome is as per Jack's wish,
4C3 * (0.5)^3 * (0.5)^1
= 0.25

Hence Susan has better chances of getting what she wants.

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